The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

This discussion is now closed.

Check out other Related discussions

probability Q

player A flips 2 coins (£1 and 50p)
player B flips 3 coins (10p, 5p and 2p)

rule 1
if player B flips 3 of the same, then he wins any of A's coins which are opposite that. Example, A flips HT and B flips TTT then B wins just the £1 coin.

rule 2
Player A wins any of B's coins which are the same face as either of his coins. Example, if A flips HT and B flips HHT then he wins 17p.

Note in rule 1 A would also take 17p.


So there are 4*8 = 32 different 5 coin outcomes.

gains/loss for B for each of the 32 outcomes;


-0.17 (x14) and (2x) of each of these; -0.15, -0.12, -0.07, -0.02, -0.05, -0.10, +1.50, +0.83, +0.33



This adds up to £1.92 and this /32 = 6p average profit per time.


Now i need to work out the chances of losing money after 10 trials for B. I thought the standard deviation would be best because i could then compare how many deviations the negative amount is from the mean expected value. But is this approach wrong?

Related discussions

Latest

Trending

Trending

Articles for you