[Finley123]

I'm having trouble with it cause i'm terrible at cancelling down

4t^3 - 16t / 3t^2 + 6t

thank youu

[donks169]

rearrange the 16t/3t^2 to get it as one factor of t [1/t^2 = t^-2]

then take out common factors:

Spoiler:

2 and t

then multiply the bracket to get a common denominator

If you get really stuck these are the stages:

Spoiler:

4t^3 - (16t)(3t^-2) + 6t
= 4t^3 - 48t^-1 +6t
= 2t(2t^2 - 24t^-2 + 3)
= 2t([2t^4 + 3t^2 - 24]/t^2)

NOTE: The maths might be wrong, but the stages are how I would do it.

[zdo0o]

i don't really know what that guy above is doing, but factorise the top and bottom and see what's common

<-- the "t"s cancel on the outside of each bracket

also notice on the top that , (difference of two squares) so rewrite that as:



so not only will "t" cancel, but also the bracket "(t+2)"

leaving:

[goldsilvy]

Originally Posted by Finley123

I'm having trouble with it cause i'm terrible at cancelling down

4t^3 - 16t / 3t^2 + 6t

thank youu

Just for the future reference - can you post your question in the Latex form, please? The basics are very easy.

e.g.

[Finley123]

Originally Posted by goldsilvy

Just for the future reference - can you post your question in the Latex form, please? The basics are very easy.

e.g.

aah yeah sure..didn't know you could do this on here - will do in the future

Originally Posted by zdo0o

i don't really know what that guy above is doing, but factorise the top and bottom and see what's common

<-- the "t"s cancel on the outside of each bracket

also notice on the top that , (difference of two squares) so rewrite that as:



so not only will "t" cancel, but also the bracket "(t+2)"

leaving:

Thank you thank you thank you!! I think I remembered factorising the 3t and 4t out but was so unsure where to go from there but I understand what you did afterwards - thanks for the help

[donks169]

Originally Posted by zdo0o

i don't really know what that guy above is doing, but factorise the top and bottom and see what's common

<-- the "t"s cancel on the outside of each bracket

also notice on the top that , (difference of two squares) so rewrite that as:



so not only will "t" cancel, but also the bracket "(t+2)"

leaving:

yeah, I kind of took it to mean

[zdo0o]

Originally Posted by donks169

yeah, I kind of took it to mean

and what would that "cancel" to?