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Reply 20
2710
How is it wrong?

Because it gives you the sum of all numbers including n, not all numbers before it.
So S(1) should be 0 and S(2) should be 1 and S(3) should be 3
But according to your formula S(1)=1 and S(2) = 3 and S(3) = 6.
Bekaboo
Because it gives you the sum of all numbers including n, not all numbers before it.
So S(1) should be 0 and S(2) should be 1 and S(3) should be 3
But according to your formula S(1)=1 and S(2) = 3 and S(3) = 6.



Doh... my excuse is not having done maths for aages :P
Lou Reed
for the nth term one, i get p×2n2p \times 2^{n-2} where p is the starting number of the series.

agreed, (note that S(n)=that for n>1) for n=1 S(1)=p obvs. which isn't included in your definition.)
Reply 23
Lou Reed
for the nth term one, i get p×2n2p \times 2^{n-2} where p is the starting number of the series.


why would you have n-2??
why not just n
and say this is for n>2
cheena
why would you have n-2??
why not just n
and say this is for n>2

what are you jabbering on about? have you even tried the question?
Reply 25
Drunk on your high rep I think Tom.
Reply 26
get a room
Reply 27
What? lol.
Tallon
Drunk on your high rep I think Tom.

only, not really.
Reply 29
lol, the amount of maths this thread actually contains is laughable.
Reply 30
cheena
get a room

:cool: :cool:

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