The Student Room Group
snoopyx
Prove that if a^x = b^y = (ab)^xy, then x + y = 1


Rewrite as xlna=ylnb=xyln(ab)x\ln a = y \ln b = xy \ln \left(ab\right) then consider xlna=xyln(ab)x\ln a = xy \ln \left(ab\right) and ylnb=xyln(ab)y \ln b = xy \ln \left(ab\right) independently which should give you two equations that you can solve simultaneously for x and y with a and b eliminated.

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