Core 2 - Geometric Progression

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  1. livingthedream's Avatar
    • Respected Member
    • Location: Bristol
    • Posts: 277
    Core 2 - Geometric Progression
    Was wondering if anyone could help me out. I have the answers but one step i just can't get my head around.

    In a geometric progression, the second term is -4 and the sum to infinity is 9. Find the common ratio.

    I have:

    ar = -4

    a/1-r = 9

    And then in the answers they jump from that to: -4/r = 9-9r
    I just can't see why, and i'm probably being silly! Anyone help me out? :confused:
  2. 0-)'s Avatar
    • Exalted Member
    • Location: London
    • Posts: 393
    Re: Core 2 - Geometric Progression
    From the first equation: a = -4/r
    From the second equation: a = 9(1-r) = 9-9r

    So we have a= -4/r = 9-9r.
  3. EoghanM's Avatar
    • Respected Member
    • Location: Northern ireland
    Re: Core 2 - Geometric Progression
    set both equations equal to 'a' then set them equal to each other then solve!!!

    your welcome
  4. livingthedream's Avatar
    • Respected Member
    • Location: Bristol
    • Posts: 277
    Re: Core 2 - Geometric Progression
    Thank you so much guys!

    I see it now. *facepalm* I was being very thick.

    Appreciate the help.
  5. Randomvariable's Avatar
    • New Member
    • Posts: 1
    Re: Core 2 - Geometric Progression
    So what's the answer please? I ended up with two answers which can't be right (i guess I'm being thick seeing as this is last year's stuff)
  6. vinvinvin's Avatar
    • Full Member
    • Posts: 106
    Re: Core 2 - Geometric Progression
    you know the sum to infinity is 9 so if you sub in both of your answers only one will equal 9.. this is the correct answer
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