The Student Room Group
Reply 1
I love how tiny that is, give me five mintues...
Reply 2
Lol, that's WAY too small to read :/
Reply 3
oh balls, this isnt working out well...

Reply 4
err... what are a and b?
can you please show the full question
Reply 6
Pheylan
err... what are a and b?


Sorry I'm not doing this too well...
The graphy shows part of the function y= a ln(bx)
Reply 7
irish_4_life
Sorry I'm not doing this too well...
The graphy shows part of the function y= a ln(bx)

oh ok

y = aln(bx)

and you have two points it goes through

0 = aln(2b)
1 = aln(4b)

so you can solve these simultaneously

ln(2b) = 0
2b = 1
b = 1/2

1 = aln(2)
a = 1/ln(2)
Reply 8
victor_b1992
can you please show the full question


It's only the top line which is missed off! which i just wrote...
The graphy shows part of the function y= a ln(bx)
ok so
Aln(2B)=0

ln(2B)=0 ln(1)=0

so b=0.5

then sub b into Aln(4B)=1
what exam broad is this
Reply 11
victor_b1992
what exam broad is this


OCR MEI, thanks for the help

Latest