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Continuity Correction

When you approximate the Binomial with the Normal distribution you have to use a continuity correction because you supposedly cannot find the probabilities of exact values under a normal distribution (as it is continuous). But surely under normal distribution,

P(x) = \frac {1}{\sigma\sqrt (2\pi)}e^\frac {-1}{2}(\frac {x-\mu}{\sigma})

doesn't this remove the need for a continuity correction?

No. Why would it?

rnd

No. Why would it?

Because the reason for the continuity correction is because you supposedly cant find probablities of exact values under Normal distribution, but you can (with the formula I posted).