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sammy3000
find the coefficient of the term x^3 in the expansion of(2+3x)^3(5-x)^3.


What have you done so far?
First expand the first and second terms using Binomial expansion. And as you are multiplying the two together, any terms higher than x^3 post-multiplication can be discarded (and in fact any constants, x, and x^2 terms can also be ignored). Add together the coefficients of the x^3 terms and you have your answer!
(2+3x)3(5x)3(2+3x)^3(5-x)^3

(2+3x)3=23+3223x+3232x2+33x3=8+36x+54x2+27x3(2+3x)^3 = 2^3 + 3*2^2*3x + 3*2*3^2x^2 + 3^3 x^3 = 8 + 36x + 54x^2 + 27x^3

(5x)3=53+352(1)x+35(1)2x2+(1)3x3=12575x+15x2x3(5-x)^3 = 5^3 + 3*5^2*(-1)x + 3*5*(-1)^2x^2 + (-1)^3 x^3 = 125 - 75x + 15x^2 - x^3

x3x^3 can come from: x3integerx^3 * integer or x2xx^2*x.

So x3x^3 coefficient = 8(1)+3615+54(75)+12527=1438*(-1)+ 36*15 + 54*(-75) + 125*27 = -143.

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