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# Draw a labelled diagram to show H-bonding between 2 molecules of liquid ammonia

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1. Liquid ammonia, NH3, and water, H20, both show H-Bonding.

So basically, i know how to draw it.. but erm could someone please clarify whether it's a or b:

a) only link two NH3 via h-bonding...h20 molecule not relevant - so don't include.

or

b) link two NH3 using a water molecule.
2. (Original post by FoOtYdUdE)
Liquid ammonia, NH3, and water, H20, both show H-Bonding.

So basically, i know how to draw it.. but erm could someone please clarify whether it's a or b:

a) only link two NH3 via h-bonding...h20 molecule not relevant - so don't include.

or

b) link two NH3 using a water molecule.
Two NH3.
3. (Original post by Kinkerz)
Two NH3.
so basically...a??

aah, cheers.

bdway,

how do i suggest the formula for sodium chlorate (vii) ??
4. (Original post by FoOtYdUdE)
so basically...a??

(Original post by FoOtYdUdE)
bdway,

how do i suggest the formula for sodium chlorate (vii) ??
Not sure.
5. (Original post by Kinkerz)

I'd go with NaClO3, but I may be wrong.
it's NaCl04 butt i dunno y. oh nvm. thnxxx.
6. (Original post by FoOtYdUdE)
it's NaCl04 butt i dunno y. oh nvm. thnxxx.
At this point, do you need to know why?
7. If you're using oxidation states:

O = -2
Na = +1
---
4(-2) + 1 = -7

So the Cl must have an oxidation number of +7, hence your sodium chlorate (vii) ion.
8. (Original post by Kinkerz)
If you're using oxidation states:

O = -2
Na = +1
---
4(-2) + 1 = -7

So the Cl must have an oxidation number of +7, hence your sodium chlorate (vii) ion.
genius!

i get it!
9. so basically if it was sodium chlorate (III) then the Cl would have an ox. no. of +3 ?? aaah and then the formula would be NaCl02 ??
10. (Original post by FoOtYdUdE)
so basically if it was sodium chlorate (III) then the Cl would have an ox. no. of +3 ?? aaah and then the formula would be NaCl02 ??
That'd be my approach, yes.

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