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Spectroscopy Question!

The vibrational wavenumber of 1H35Cl is 2990.95cm-1. Calculate the wavenumber for the isotopomers: 1H37Cl, 2H35Cl and 2H37Cl. Comment on the values you obtain and the consequences on the appearance of the IR spectrum of HCl. Exact relative atomic masses and natural abundances: 1H 1.00794 (99.99%), 2H 2.0140 (0.01%), 35Cl 34.9689 (75%), 37Cl 36.9659 (25%).

Ive tried calculating the force constant from this data using the formula wavenumber= 1/(2Pi x c) x square root of (k/u)
where u is reduced mass, yet am having a few difficulties. Any suggestions would be great help! thanks
Reply 1
Avatar for oceane
oceane
10
What difficulties are you having cos you're going about it the right way - it's just the reduced mass that's different in each case.
Ah okay, is the force constant the same for each molecule?
Reply 3
Avatar for shengoc
shengoc
12
ilikechocolate123
Ah okay, is the force constant the same for each molecule?


the bond length wouldn't differ much as they are just isotope(ie no change to electronic configuration) - infact i don't think it would change at all,

if bond length stays constant => bond strength, hence k remains constant.
Sorry to dredge this up - but what is c ?

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