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Maths C4 question
A curve has parametric equations
x=t + 1/t y=t+1
where t is not equal to 0
express dy/dx in terms of t and hence find the values of t for which the gradient of the curve is 2.
dx/dt = 1 + -t^-2
dy/dt = 1
dy/dx = dy/dt x dt/dx
Once you do get a correct value for dy/dx i presume you just equate that 2.
I dont think i have even done this differentiating part right
Can anyone explain this question to me? thankyou
x=t + 1/t y=t+1
where t is not equal to 0
express dy/dx in terms of t and hence find the values of t for which the gradient of the curve is 2.
dx/dt = 1 + -t^-2
dy/dt = 1
dy/dx = dy/dt x dt/dx
Once you do get a correct value for dy/dx i presume you just equate that 2.
I dont think i have even done this differentiating part right
Can anyone explain this question to me? thankyou
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