The Student Room Group
Reply 1
b[a(1 - b^k)/(1 - b) + Nb^k] + a
= ba(1 - b^k)/(1 - b) + a + N b^(k + 1)
= [a/(1 - b)]*[b(1 - b^k) + (1 - b)] + N b^(k + 1)
= [a/(1 - b)]*[1 - b^(k + 1)] + N b^(k + 1)
Reply 2
argh, thankyou.

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