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intergration of trigs
Show that integral of 1 / ( 1 - cos 2X) = sqr 3/ 2 - 1/2 limit btw Pie/6 to Pie/4
P.s I would like to know if the formulas for standard integrals will be given in the mathematical booklet
manifest.
P.s I would like to know if the formulas for standard integrals will be given in the mathematical booklet
manifest.
cos(2x) = 1 - 2sin^2(x)
1/(1 - cos(2x)) dx
= 1/(2sin^2(x)) dx
= (1/2) cosec^2(x) dx
= (1/2) [ -cot(x) ] (from pi/6 to pi/4)
= (1/2) (sqrt(3) - 1)
You will probably find cosec^2(x) dx = -cot(x) + c and similar results in your formula booklet.
Edexcel formula booklet:
http://www.edexcel.org.uk/VirtualContent/83441/Formulae_book_Revised_Specification.pdf
1/(1 - cos(2x)) dx
= 1/(2sin^2(x)) dx
= (1/2) cosec^2(x) dx
= (1/2) [ -cot(x) ] (from pi/6 to pi/4)
= (1/2) (sqrt(3) - 1)
You will probably find cosec^2(x) dx = -cot(x) + c and similar results in your formula booklet.
Edexcel formula booklet:
http://www.edexcel.org.uk/VirtualContent/83441/Formulae_book_Revised_Specification.pdf
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