The Student Room Group
Reply 1
modulus 12
argument 2π/3


z = 12(cos(2π/3) + isin(2π/3)) = 12(-1/2+i√3/2) = -6 +6√3i

modulus 4
argument -π/3


z = 4(cos(-π/3) + isin(-π/3)) = 4(1/2-i√3/2) = 2 - 2√3i
Reply 2
...using mod arg form
Reply 3
of course, silly me, thanks !

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