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Dr hannibal lecter
I need to find 77x=1mod 5 where x is an integer

then it is the same as 2x=1mod5

why is this ?(i can see both leaves the same remander for values of x , )

thnaks


One way is consider 75x mod 5. What does that equal?

Then subtract the appropriate representation from each side.
Reply 2
Dr hannibal lecter
I need to find 77x=1mod 5 where x is an integer

then it is the same as 2x=1mod5

why is this ?(i can see both leaves the same remander for values of x , )

thnaks

75x0(mod5)75x \equiv 0(mod 5)
therefore:
77x2x(mod5) 77x \equiv 2x(mod5)
ghostwalker
One way is consider 75x mod 5. What does that equal?

Then subtract the appropriate representation from each side.

Papkin
75x0(mod5)75x \equiv 0(mod 5)
therefore:
77x2x(mod5) 77x \equiv 2x(mod5)

Damm!! knew it was something very obvious .thanks:smile: both of you

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