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chemistry help moles !
can anyone help me with this question plz
Calculate the valoume of 2 mole dm-3 nitric acid required to react with 20.5 g copper (ll) carbonate.
CuCO3 + 2HNO3 = Cu(NO3) + CO2 + H20
HELP PLZ
thanx x
Calculate the valoume of 2 mole dm-3 nitric acid required to react with 20.5 g copper (ll) carbonate.
CuCO3 + 2HNO3 = Cu(NO3) + CO2 + H20
HELP PLZ
thanx x
What have you done so far? post working!
CuCO3= 123.5 Mr
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
(2 moles of HNO3 react with one CUCO3 so x2 moles.)
2HNO3 has 0.332 moles
Concentration is 2mol dm^-3
Use this formula: Moles= ConcentrationxVolume
rearrange to: Moles/concentration=volume
0.332mol/2 moldm-3=0.166dm^-3
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
(2 moles of HNO3 react with one CUCO3 so x2 moles.)
2HNO3 has 0.332 moles
Concentration is 2mol dm^-3
Use this formula: Moles= ConcentrationxVolume
rearrange to: Moles/concentration=volume
0.332mol/2 moldm-3=0.166dm^-3
(edited 13 years ago)
uxa595
Moles = Concentration v Volume
Therfore, Moles/Concentration=Volume
CuCO3= 123.5 Mr
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
Im sure you can finish it from there
Therfore, Moles/Concentration=Volume
CuCO3= 123.5 Mr
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
Im sure you can finish it from there
thanx
uxa595
look at it now
i edited the post :P
its all come back to me
that was a very easy one
i edited the post :P
its all come back to me
that was a very easy one
thnx again
uxa595
CuCO3= 123.5 Mr
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
(2 moles of HNO3 react with one CUCO3 so x2 moles.)
2HNO3 has 0.332 moles
Concentration is 2mol dm^-3
Use this formula: Moles= ConcentrationxVolume
rearrange to: Moles/concentration=volume
0.332mol/2 moldm-3=0.166dm^-3
Moles= Mass/Mr
Moles = 20.5/123.5 = 0.166mol
(2 moles of HNO3 react with one CUCO3 so x2 moles.)
2HNO3 has 0.332 moles
Concentration is 2mol dm^-3
Use this formula: Moles= ConcentrationxVolume
rearrange to: Moles/concentration=volume
0.332mol/2 moldm-3=0.166dm^-3
You seem clever:P you would happen to know how to convert mol dm-3 to gcm-3 by any chance?
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