How do find the minimum/maximum point on a curve? (C1 EDEXCEL)
Maths and statistics discussion, revision, exam and homework help.
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How do find the minimum/maximum point on a curve? (C1 EDEXCEL)
How do find the minimum/maximum point on a curve? and can you give an example please
By the way keep this to Core 1 level/AS level
Exam board is edexcel.
Im a bit confused because the book doesn't mention anything about them, but sometimes I need to calculate them.
Thanks -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)
when you have a function, y=x^2 or something like that, you diffrentiate the function and make dy/dx=0, thats to find the stationary points, if you then diffrentiate again(this example is not useful for this bit) and you sub in your values obtained from dy/dx=0 then if the outcome number is above 0 then it is a minimum, if it is below 0 then it is a maximum. Look in the spoiler for my example
Spoiler:EDIT: sorry its a bit messy, I tried to avoid latex because its hard to use and annoying at timesShowy=x^3 - 2x, dy/dx = 3x^2 - 2, 3x^2 - 2 = 0, x^2 = 2/3 so x = plus or minus root 2/3. find d^2y/dx^2, this means differentiating 3x^2 - 2, this gives you 6x, sub the plus or minus root 2/3 in and work out which one is a maximum or a minimum
Last edited by Eloades11; 08-12-2010 at 09:19. -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)
http://tutorial.math.lamar.edu/Class...calPoints.aspx
http://tutorial.math.lamar.edu/Class...MaxValues.aspx
Awesome site for other stuff too
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Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)What happens when you second differentiate for example: -6x+2(Original post by Eloades11)
when you have a function, y=x^2 or something like that, you diffrentiate the function and make dy/dx=0, thats to find the stationary points, if you then diffrentiate again(this example is not useful for this bit) and you sub in your values obtained from dy/dx=0 then if the outcome number is above 0 then it is a minimum, if it is below 0 then it is a maximum. Look in the spoiler for my example
Spoiler:EDIT: sorry its a bit messy, I tried to avoid latex because its hard to use and annoying at timesShowy=x^3 - 2x, dy/dx = 3x^2 - 2, 3x^2 - 2 = 0, x^2 = 2/3 so x = plus or minus root 2/3. find d^2y/dx^2, this means differentiating 3x^2 - 2, this gives you 6x, sub the plus or minus root 2/3 in and work out which one is a maximum or a minimum
you get -6
you cannot sub any of the values obtained from first differentiation. what to do then?
thanks! -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)y=-6x + 2(Original post by dream123)
What happens when you second differentiate for example: -6x+2
you get -6
you cannot sub any of the values obtained from first differentiation. what to do then?
thanks!
dy/dx = -6
when dy/dx=0
-6=0?
no stationary points, as you should already know if you just sketch the graph of -6x + 2
(cant find maximum and minimum points if theres no stationary pionts!)
hope this helped -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)Use of differentiation to solve problems with Max/Min points is part of C2 not C1 for Edexcel(Original post by jayseanfan)
How do find the minimum/maximum point on a curve? and can you give an example please
By the way keep this to Core 1 level/AS level
Exam board is edexcel.
Im a bit confused because the book doesn't mention anything about them, but sometimes I need to calculate them.
Thanks
You might be expected to use completed square to find the minimum point of a quadratic but that's all. [ the min of (x + p)^2 + q occurs at (-p,q) ]
e.g. x^2 + 6x + 5
= (x + 3)^2 - 4
minimum is at (-3, -4)
If you are asked to sketch a graph of a given function you will be required to show where it crosses the axes
If you are asked to sketch a transformation of a graph you are reuired to label the new coordinates of points labelled on the original graphLast edited by gdunne42; 08-12-2010 at 11:46. -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)If I knew this I would have pointed it out, but im on OCR doing A2 at the moment, similar topics though right? Plus people assumably doing C1 will do C2, but it would take a bit of pressure off if you learnt them in order. I ended up revising C4 for my C3 mock :/(Original post by gdunne42)
Use of differentiation to solve problems with Max/Min points is part of C2 not C1 for Edexcel -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)Wait, I'm doing Edexcel Maths, C1 and I've never been asked to calculate this. There's nothing in the book about it either. Can someone just confirm whether or not this could be in the exam, because I'm confused now, and we haven't been taught this(Original post by jayseanfan)
How do find the minimum/maximum point on a curve? and can you give an example please
By the way keep this to Core 1 level/AS level
Exam board is edexcel.
Im a bit confused because the book doesn't mention anything about them, but sometimes I need to calculate them.
Thanks
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Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)Yep pretty much the same topics on the different awarding bodies but differences in which are in C1 and which in C2. Finding turning points/stationary points by setting dy/dx = 0 is C2 for Edexcel. Finding d^2y/dx^2 of a function is in Edexcel C1 and has occassionally been asked in the exam but you don't learn to do anything with it in terms of max/min points until C2. They will eventually cover it but don't need to know it for their January C1 exam.(Original post by Eloades11)
If I knew this I would have pointed it out, but im on OCR doing A2 at the moment, similar topics though right? Plus people assumably doing C1 will do C2, but it would take a bit of pressure off if you learnt them in order. I ended up revising C4 for my C3 mock :/
Specification: http://www.edexcel.com/migrationdocu...2%20180510.pdf -
Re: How do find the minimum/maximum point on a curve? (C1 EDEXCEL)
e.g.
y = x^2 + 6x, find the coordinates of the minimum point
start by differentiating (dy/dx will give you the formula for the gradient)
dy/dx = 2x + 6
minimum point => dy/dx = 0 (remember, at minimum/maximum points the gradient is 0 since at this particular instant the graph isn't increasing or decreasing)
therefore 2x + 6 = 0
2x = 6
x = 3
sub x = 3 into y = x^2 + 6x to get y = 27
the coordinates of your minimum point are therefore (3,27)
(main point: dy/dx will give you the formula for the gradient)Last edited by the maths guy; 08-12-2010 at 15:10.