(Original post by raheem94)
Is the question 10 (a) correct in the unofficial mark scheme. I have checked my solution but my graph of the equation y=x^2 (7-x) is not matching with the graph drawn in the mark scheme.
Yes, but the graph of bends again before intersecting the other one - that is not how it is meant to be. is , so it is the other way around and, if you put x and y equal to zero, you'll find where it crosses both the x axis and the y axis. What does your version look like? If it is an S shape, then it is wrong because is backwards.
Last edited by MostCompetitive; 26-12-2010 at 21:28.
(Original post by Zoe17)
Why on 10.c are you supposed to choose 4-2/3 and not 4+2/3?
Sorry, not sure if you know but you seemed to know the previous answer lol
From the sketch you did part a, you should see that the x co-ordinate of the point of intersection is less than 4. There is another point of intersection that is below the x-axis, and the problem with that is that it is below the x axis - the question says that both co-ordinates (x and y) are positive. Therefore, the x co-ordinate of the point of intersection the Q is asking for must be
Last edited by MostCompetitive; 05-01-2011 at 19:22.