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RSS  Maths revision, coursework or discussion you will find help in here.
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Old 16-11-2005: 16th November 2005 19:04 #1 
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Default C3 Ex 6c Question 8
 
can anyone tell me how to do this, its a diagram so i cant put it up thanks a million
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Old 16-11-2005: 16th November 2005 19:13 #2 
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Old 16-11-2005: 16th November 2005 19:18 #3 
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Old 16-11-2005: 16th November 2005 19:44 #4 
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a) CD= AD - AC

AD=6/cosθ
=6secθ

AC=6cosθ

since CD= AD - AC
=6secθ - 6cosθ
=6(secθ -cosθ ) as required.
 
 
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