OCR F321 - 23rd May
Chemistry exam discussion - share revision tips in preparation for GCSE, A Level and other chemistry exams and discuss how they went afterwards.
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Re: OCR F321 - 23rd MayChlorine in cyclohexane is yellow (most reactive)(Original post by thefirstnotlastsamurai)
I haven't read this thread, so i apologize if my question has already been asked, but just wondering if someone could clarify all the colours you get when you react the halogens together, and what happens if you add cyclohexane. Different books just say different things.
Appreciate it.
Bromine in cyclohexane is orange
Iodine in cyclohexane is purple (least reactive) -
Re: OCR F321 - 23rd Mayfghh(Original post by sixthformer)
guys, they won't ask us anything not in the book
if they do, then we'll hunt them. -
Re: OCR F321 - 23rd May
Oxidation Numbers
All elements in their natural state have the oxidation number zero.
ie Hydrogen, H2 oxidation number is 0
Oxidation numbers of the atoms of any molecule add up to zero.
ie Water H2O, sum of oxidation numbers = 0
Oxidation numbers of the components of any ion add up to the charge of that ion.
ie Sulphate, SO4 2- sum of oxidation numbers = -2
The rules in order of priority
1. Oxidation numbers of elements in groups 1, 2 and 3 are always +1, +2, +3
2. The oxidation number of Fluorine is always -1
3. The oxidation number of Hydrogen is usually +1
4. The oxidation number of Oxygen is usually - 2
5. The oxidation number of Chlorine is usually -1
Examples
Deduce the oxidation number of Cl in NaCal
Sum of oxidation numbers must add up to zero.
Therefore Na must be +1
Oxidation number of Cl must balance this
Therefore oxidation state of Cl in NaCl is -1
N2O - O is -2, there are 2 N, so each must be +1
SO4 2- Four O at -2 each gives a total of -8. The ion has an overall charge of -2, so the Oxidation number of S is +6.
CO3 2- Three O at -2 each gives a total of -6. The ion has an overall charge of -2, so the Oxidation number of C is +4.
MnO4 - Four O at -2 each gives a total of -8. The ion has an overall charge of -1, so the Oxidation number of Mn is +7.
Cr2O7 2- Seven O at -2 each gives a total of -14. The ion has an overall charge of -2, so the Oxidation number of each Cr is +6.
NH3 - H is +1, there are 3 H, so N must be -3
KNO3 - O is -2 and K has its normal oxidation number of +1. KNO3 has no overall charge, so N must balance -6 from the 3 O and + 1 from the K. N is +5. -
Re: OCR F321 - 23rd MayHow to calculate the 'water of crystalisation' so work out the 'x' in •xH2O.(Original post by kingam)
anyone what do we need to know on water of crystallisation
And just know the definitions of hydrous and anhydrous (with/without water respectively) -
Re: OCR F321 - 23rd MayI thought chlorine was light green??(Original post by EternalDoom)
Chlorine in cyclohexane is yellow (most reactive)
Bromine in cyclohexane is orange
Iodine in cyclohexane is purple (least reactive) -
Re: OCR F321 - 23rd MayCheck the mark scheme, they accept 2-3 colours, my textbook taught me yellow(Original post by dream_merchant)
I thought chlorine was light green?? -
Re: OCR F321 - 23rd Maychlorine is pale green in both water and cyclohexane!(Original post by dream_merchant)
I thought chlorine was light green?? -
Re: OCR F321 - 23rd Mayits brown your right then in cyclohexane it pink(Original post by dream_merchant)
what colour is iodine in water. Brown? -
Re: OCR F321 - 23rd MayPurple?!(Original post by kingam)
its brown your right then in cyclohexane it pink -
Re: OCR F321 - 23rd Mayin water:cl2 is pale green..Br2 is orange and I2 is brown(Original post by dream_merchant)
what colour is iodine in water. Brown?
in cyclohexane:cl2 is pale green..Br2 is orange and I2 is violet. only colour of iodine is different the other two are the same in both water and cyclohexane :-) -
Re: OCR F321 - 23rd MayThanks(Original post by sarian2)
in water:cl2 is pale green..Br2 is orange and I2 is brown
in cyclohexane:cl2 is pale green..Br2 is orange and I2 is violet. only colour of iodine is different the other two are the same in both water and cyclohexane :-)
and ions are colourless correct?Last edited by dream_merchant; 22-05-2011 at 16:21. -
Re: OCR F321 - 23rd Maysay you have a solution of bromine and you add it to a solution of sodium iodide you would get(Original post by sarian2)
CAN SOMEBODY TEACH ME HOW TO WRITE IONIC EQUATIONS PLEASE?thanks x
Br2 + 2I^- =====> 2Br^- + I2
because the bromine is just in solution so you just write Br2, but as the iodine is in an ionic compound, it is an iodide ion so you write it as I^- . Then as bromine is more reactive than iodine, it displaces the iodide ions and becomes bromide ions Br^- leaving the iodine now in solution as I2.
The '2' in front of the ions is to balance the equation
hope this helps!
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Re: OCR F321 - 23rd Mayhow many attempts r u allowed? and if this s ur 4th attempt? does the highest out of da 4 attempts count or it is da highest out of the last 2 attempts? i want to know incase i have to resit this again as i need a minimum of an A on his to pull up my overall mark in the subject seeing as i got a U in practcal?(Original post by greenford)
I have this exam tomorrow... haven't done any revision... have such a bad flu that cant even move.. I got 68 in the Jan one.... 4th time retake...
... hope its an easy paper

... hope its an easy paper
