[soup]

(Original post by Midnightsk010)
Did anybody get P to be less than -108 and less than 13.

That was so damn hard

What did everyone get for the integration question? How did everyone attempt it?

I got 21 and one twelfth. Integrated between -2 and 0 (curve - line) and added it to the integrated between 0 and 3 (line - curve)

[kirstymcmanus]

The maths department at my school done the paper once we got out, so i've marked mine against it, and paper 1 i only got two objective questions wrong, plus i lost 5 marks in paper 2, so an A for that one probs, but paper 2 will drag me WAAAAAY down. darn i might try and post the papers actually, if someone else doesn;t do it in the next like 5 mins

[akalasa]

EDIT: Sorry, looks like someone beat me to it, and posted the correct solution - mine is slightly off - IGNORE!

For the last question, I worked out the two centers (-1,1) and (2,-3), then I did distance formula which worked out to be 5. Then so they don't intersect, the radius of C2 would have to be less than 6 (since 11-5=6). I then substituted this into the formula r<square root of (g^2+f^2-c), which worked out that 6<square root of (13-p). Therefore p must be less than 14 (can't square root a negative).

so therefore, 36<13-p
23>-p
p>-23

-23<p<14

I'm fairly confident that's how it is done, but if not then correct me please! Can't go into advanced higher with faulty higher maths! :P lol

[NaturalDisaster]

Ok, seeing everyone elses answers is scaring the **** out of me. Think I'll just creep away now to cry and revise German...

[soup]

(Original post by akalasa)
For the last question, I worked out the two centers (-1,1) and (2,-3), then I did distance formula which worked out to be 5. Then so they don't intersect, the radius of C2 would have to be less than 6 (since 11-5=6). I then substituted this into the formula r<square root of (g^2+f^2-c), which worked out that 6<square root of (13-p). Therefore p must be less than 14 (can't square root a negative).

so therefore, 36<13-p
23>-p
p>-23

-23<p<14

I'm fairly confident that's how it is done, but if not then correct me please! Can't go into advanced higher with faulty higher maths! :P lol

Surely if p = 13.5 you'd still be square rooting a negative? And 13-p > 0 for a radius to exist anyway.

[Midnightsk010]

(Original post by soup)
I got 21 and one twelfth. Integrated between -2 and 0 (curve - line) and added it to the integrated between 0 and 3 (line - curve)

That's what I did!
Thanks!!

[akalasa]

(Original post by soup)
Surely if p = 13.5 you'd still be square rooting a negative? And 13-p > 0 for a radius to exist anyway.

Yep, you're right, just noticed that. Thanks!
However, I wrote down 13>p on my paper so I'll get the mark I thought I lost!

[Inheritorz]

(Original post by Quintro)
Here is links to Paper 2... Sorry for my lack of iPhone camera photography skillz....

http://imageshack.us/f/714/img0202oi.jpg/

http://imageshack.us/f/14/img0203md.jpg/

http://imageshack.us/f/705/img0204go.jpg/

Cheers Dude - Legend

[morganalex]

I only have Paper 2 sorry, I also apoligise for how crumpled it is - it was very windy outside!







Hope they are okay for everyone and I bet you all did great, stop worrying!

[morganalex]

(Original post by Quintro)
Here is links to Paper 2... Sorry for my lack of iPhone camera photography skillz....

http://imageshack.us/f/714/img0202oi.jpg/

http://imageshack.us/f/14/img0203md.jpg/

http://imageshack.us/f/705/img0204go.jpg/

Sorry I never noticed you'd already posted this, I never read everything before posting the photos, my bad! x

[INeedToLoseWeight]

This thread has made me realise how much I got wrong... great!!

[john4994]

(Original post by akalasa)

I'm also wondering if anyone can explain something to me - for paper 1, with the question about the discriminant being 23, is that rational or not? Couldn't work that one out at all :P

If the discriminant is a square number, it is rational, otherwise it is not. Thats the one thing i remembered from my last minute revision this morning!

Paper one was pretty good - think i only dropped around 5 or 6 marks

Paper 2 was going very well - first 4 questions i think i have got all correct...... then i turned to the last page which was shocking. don't think i've got any for the log question, i integrated the wrong thing for the 7 mark trig integration, and probs only got 3 for the circles one.

[judzi]

(Original post by Kelsper)
This came from the formula of getting the radius of a circle: sqroot[x^2 + y^2 (center points) - c (in this case, p)]

because the second circle lied in the first circle, the radius of the second circle had to be less then 11 (the radius of the first circle) or root 121.

Essentially they thought that since x^2 + y^2 is 13, p would have to add 108 on (thus why it is negative) so they could say that P>-108 for the radius to be less than 11.

I don't know if it is right, however.

I done this, hopefully that's right....

[Quintro]

I reckon the percentage required for an A this year will be really low to be honest, very very few people done well on the last page.

And to the people who are saying the answer to the last question is p > -108, isn't that assuming that both C1 and C2 share the same centre? I got it wrong too though..

EDIT: (Although I don't know for a fact if this is right or wrong, I just think it is wrong)

[morganalex]

Did anyone else spend a while on question 6A just looking at it like oh my god before realising it was the wave function? That stupid R instead of a k put me off!

[judzi]

(Original post by Quintro)
I reckon the percentage required for an A this year will be really low to be honest, very very few people done well on the last page.

And to the people who are saying the answer to the last question is p > -108, isn't that assuming that both C1 and C2 share the same centre? I got it wrong too though..

EDIT: (Although I don't know for a fact if this is right or wrong, I just think it is wrong)

Yeah, i just realized the thing to do with the centres, pity I didn't realize this in the exam

[Alex259]

Does anyone know the percentage cut offs like what do you need to get an A B and C in Higher Maths

[soup]

(Original post by Alex259)
Does anyone know the percentage cut offs like what do you need to get an A B and C in Higher Maths

It changes every year.. so it will change this year

[BoyceAvenue]

I have failed.
Oh well, always next year, hopefully it's better then and I understand more ~

[soup]

http://img84.imageshack.us/g/imgp1059t.jpg/

That's the multiple choice, hopefully you can see it.