[GεεRTHAN]

As above really...need help....not getting actual answer... :o

[Simba]

Textbook? Post the question here please, bearing in mind most people probably won't have the same textbook as you !

[GεεRTHAN]

Sketch the following and find the area of the finite region or regions bounded by the curves and the x-axis: y = x (x - 2) (x - 5) .

[GεεRTHAN]

Anyone for the above listed question...?

[Aitch]

Originally Posted by lgeerthan

Anyone for the above listed question...?

curve cuts x-axis at x= 0,2,5. Sketch curve.
Enclosed area, therefore limits, between x=2 and x=0

∫x³ -7x² +10x dx
=¼x^4 -(7/3)x³+5x²
limits 2 and 0 give

4 -(56/3) +20 = 16/3

[GεεRTHAN]

Originally Posted by Aitch

curve cuts x-axis at x= 0,2,5. Sketch curve.
Enclosed area, therefore limits, between x=2 and x=0

∫x³ -7x² +10x dx
=¼x^4 -(7/3)x³+5x²
limits 2 and 0 give

4 -(56/3) +20 = 16/3

And then isnt there a limit of 2 and 5?? :o

[Aitch]

Originally Posted by lgeerthan

And then isnt there a limit of 2 and 5?? :o

Oops! Yes!

¼x^4 -(7/3)x³+5x²
limits 5 and 2 give

[(625/4)-(875/3)+125]-[16/3]
=(-)15.75