The Student Room Group
Reply 1
Textbook? Post the question here please, bearing in mind most people probably won't have the same textbook as you :wink: !
Reply 2
Sketch the following and find the area of the finite region or regions bounded by the curves and the x-axis: y = x (x - 2) (x - 5) .

:smile:
Reply 3
Anyone for the above listed question...?
Reply 4
lgeerthan
Anyone for the above listed question...?


curve cuts x-axis at x= 0,2,5. Sketch curve.
Enclosed area, therefore limits, between x=2 and x=0

∫x³ -7x² +10x dx
=¼x^4 -(7/3)x³+5x²
limits 2 and 0 give

4 -(56/3) +20 = 16/3
Reply 5
Aitch
curve cuts x-axis at x= 0,2,5. Sketch curve.
Enclosed area, therefore limits, between x=2 and x=0

∫x³ -7x² +10x dx
=¼x^4 -(7/3)x³+5x²
limits 2 and 0 give

4 -(56/3) +20 = 16/3


And then isnt there a limit of 2 and 5?? :redface:
Reply 6
lgeerthan
And then isnt there a limit of 2 and 5?? :redface:


Oops! Yes!

¼x^4 -(7/3)x³+5x²
limits 5 and 2 give

[(625/4)-(875/3)+125]-[16/3]
=(-)15.75

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