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Log PROBLEMS!!

could somebody explain to me why x=ln(1/4) is the same as 2ln(2)

Thankyou
Reply 1
Avatar for gozatron
gozatron
16
Ln(x/y) = Ln(x) - Ln(y)

Ln(x^y) = yLn(x)

Ln(1) = 0
(edited 12 years ago)
Reply 2
Avatar for hwalker37
hwalker37
Work it out with a pencil......Oh wait :colone:


In all truth, what the guy above me said^^^ :biggrin:

Edit: It would be -2ln2 though as it is 0 - ln4 = -ln4
(edited 12 years ago)
Reply 3
Avatar for Dekota-XS
Dekota-XS
2
Ln(1/4) does not equal 2ln(2).
Reply 4
Avatar for hwalker37
hwalker37
Original post by Dekota-XS
Ln(1/4) does not equal 2ln(2).


Stick a minus in and it's all gravy baby :colone:
Reply 5
Avatar for ElMoro
ElMoro
18
Original post by Taylor_R
could somebody explain to me why x=ln(1/4) is the same as 2ln(2)

Thankyou


Surely, it's -2ln(2) ?
Reply 6
Avatar for Taylor_R
Taylor_R
OP
Yeah you are right :smile: How did you get it though, i had to look in the back of my book then ? I dont understand all of this stuff.
Reply 7
Avatar for Taylor_R
Taylor_R
OP
Original post by ElMoro
Surely, it's -2ln(2) ?


^^
Original post by Taylor_R
^^


Yeah, the corrections of it being −2ln(2)-2ln(2) are correct.

It's obtained through the following:

ln(14)=ln1−ln4ln(\frac{1}{4}) = ln1-ln4

ln1=0ln1=0, so we're left with −ln4-ln4

−ln4-ln4 can be written as −ln(2)2-ln(2){^2}, which can be written as −2ln2-2ln2.

(C2 log laws will explain the process(es)).

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