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Physics Question, please help...

2. A manned rocket comes to a halt and then begins to fall towards Earth. After some time, at a height of 300 m above the surface of the Earth, it is falling directly downwards at a velocity of 100 m s-1. At this point the pilot decides to fire the rocket engines such that he gives himself an
upward acceleration of 9.81 m s-2.

Take g=9.81 m s-2


a) Show that he crashes by calculating the stopping distance.
Do you know all the relevant equations? v=u+at ect remember for these equations to decide which direction is positive, say up, and so its -100ms-1 . For the stopping distance work out when the distance travelled untilthe point where v=0. What does this tell you if hes 300m above the ground to begin with?
Reply 2
Avatar for MurMan
MurMan
The rocket is traveling at 100m/s under an acceleration of 9.81 towards the earth. When the engines fire at and acceleration upward of 9.81 they cancel the gravity and create an acceleration of 0. However this doesn't mean that the rocket stops, it continues to fall at constant speed and hits the earth at 100m/s
Reply 3
Avatar for R.Fanatic
R.Fanatic
OP
Thanks. got it.

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