Results are out! Find what you need...fast. Get quick advice or join the chat
Hey! Sign in to get help with your study questionsNew here? Join for free to post

Simple Maths questions.

Announcements Posted on
The Grow your Grades contest is here, join in to help each other achieve your study goals 22-01-2015
  1. Offline

    ReputationRep:
    1. Simplify √24 +√6. I got 5√12...is this correct?

    2. Express (fraction) 36 which is over 5-√7 in the form a+b√7, where a and b are integers. I got 10+2√7...is this correct?

    3. Make X the subject of this formula: (its a fraction) 'a', over (x-b)^2=c (the whole fraction equals C, not the (x-b)^2)

    ^^ I cant seem to get a reasonable looking answer for no.3.
  2. Offline

    ReputationRep:
    1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

    2. Yes it is

    3. What answer did you get?
  3. Offline

    ReputationRep:
    simple?
  4. Offline

    ReputationRep:
    (Original post by CJN)
    1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

    3. What answer did you get?
    I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
    Right or not? If not whats the right answer?

    And is the answer to Q1. 4√6?

    Thanks.
  5. Offline

    ReputationRep:
    √24 + √6 is not 4√6
    √24 => √4√6 => 2√6

    2√6 + √6, which is 3√6 not 4
  6. Offline

    ReputationRep:
    I got 3√6 for Q1

    √24 broken down to √6*√4, so that's 2√6.

    2√6 + √6 = 3√6

    My maths is a bit rusty so I don't exclude being completely wrong
  7. Offline

    ReputationRep:
    (Original post by Saif95)
    I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
    Right or not? If not whats the right answer?

    And is the answer to Q1. 4√6?

    Thanks.
    What is root 24 in terms of root 6?
  8. Offline

    ReputationRep:
    (Original post by Nucleo)
    √24 + √6 is not 4√6
    √24 => √4√6 => 2√6

    2√6 + √6, which is 3√6 not 4
    (Original post by ryan84)
    What is root 24 in terms of root 6?
    Yh thanks I get it now...

    can you tell me if my answer to the 3rd question was right? if not what is it?
    thanks.
  9. Offline

    ReputationRep:
    (Original post by Saif95)
    Yh thanks I get it now...

    can you tell me if my answer to the 3rd question was right? if not what is it?
    thanks.
    Not sure what you are doing, but:

     \dfrac{a}{(x-b)^2} = c


     c \times (x - b)^2 = a


     (x - b)^2 = \dfrac{a}{c}


     x - b = \sqrt{\dfrac{a}{c}}


     x = \sqrt{\dfrac{a}{c}} + b

Reply

Submit reply

Register

Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?
  2. this can't be left blank
    this email is already registered. Forgotten your password?
  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By joining you agree to our Ts and Cs, privacy policy and site rules

  2. Slide to join now Processing…

Updated: October 11, 2011
New on TSR

Take a selfie for the student vote

Join your community montage

Article updates
Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.