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implicit differentiation

x^2+2xy+y^2=4x
Prove dy/dx is 2/(x+y) - 1

I have shown my working in the attachment. I am stuck on the final step
Reply 1
You've done all the hard stuff, all you need to do now is rearrange to get dydx\dfrac{dy}{dx} on its own (and simplify your answer by cancelling common factors).
Reply 2
Original post by nuodai
You've done all the hard stuff, all you need to do now is rearrange to get dydx\dfrac{dy}{dx} on its own (and simplify your answer by cancelling common factors).


So you move the 2x+2y to the other side to give dy/dx=4-2x-2y/2x+2y.

Cancelling out gives 2-x-y/x+y

This still isn't correct though...

What do I do next
Reply 3
Original post by nasira372
Cancelling out gives 2-x-y/x+y

This still isn't correct though...


Yes it is. What makes you think it isn't?
Original post by nasira372
So you move the 2x+2y to the other side to give dy/dx=4-2x-2y/2x+2y.

Cancelling out gives 2-x-y/x+y

This still isn't correct though...

What do I do next


If your book shows you the answer, you might compare what you have and ask 'what do I have to do to change my answer into theirs?'
Reply 5
Original post by nuodai
Yes it is. What makes you think it isn't?


I get 2-x-y/x+y

I need the final answer to be 2/x+y -1

What do I do to my answer to get the required answer
Reply 6
Original post by nasira372
I get 2-x-y/x+y

I need the final answer to be 2/x+y -1

What do I do to my answer to get the required answer


Oh; well they're the same thing. Note that you can write 2xy2-x-y as 2(x+y)2-(x+y) if you want to rearrange it.
Reply 7
Original post by nuodai
Oh; well they're the same thing. Note that you can write 2xy2-x-y as 2(x+y)2-(x+y) if you want to rearrange it.


From this line

2x + 2y + dy/dx(2x +2y) = 4

You could have seen

2(x + y)(1 + dy/dx) = 4

1 + dy/dx = 2/(x+y)

dy/dx = 2/(x+y) - 1
Reply 8
Original post by TenOfThem
From this line

2x + 2y + dy/dx(2x +2y) = 4

You could have seen

2(x + y)(1 + dy/dx) = 4



TBH, I still dont see it even though you've pointed it out to me. The sudden appearance of the 1 is very confusing. I'd still get 3/4 marks though for what I did. Just not the final step :frown:
Reply 9
Original post by nuodai
Oh; well they're the same thing. Note that you can write 2xy2-x-y as 2(x+y)2-(x+y) if you want to rearrange it.


Thanks a lot,

I never would have thought about doing that
(edited 12 years ago)

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