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AS level coordinate geometry

The curve C has the equation:
y=x^2 + ax + b,

where a and b are constants.

Given that the minimum point of C has coordinates (-2, 5), find the values of a and b.

How would i go about doing this?
Reply 1
Using completing the square

Do you know how (xp)2+q(x-p)^2 + q relates to the turning point



I am assuming that you have not learnt differentiation yet
Reply 2
Original post by TenOfThem
Using completing the square

Do you know how (xp)2+q(x-p)^2 + q relates to the turning point



I am assuming that you have not learnt differentiation yet


I have, i solved it by differentiation dy/dx = 2x + a, a = 4 then sub to get b = 9, but in the mark scheme it's only showing the completing the square method, which i've never been taught. Though the answers are still correct...
What's your query then?
Reply 4
Original post by ViralRiver
What's your query then?


How do you solve it by completing the square.
Reply 5
Original post by lemonpwns1
How do you solve it by completing the square.


Well y=(xp)2+qy = (x-p)^2 + q

Has a turning point at (p,q)

So ... if you expand this (having put your minimum point in for p and q) you can equate to find a and b
Reply 6
Original post by TenOfThem
Well y=(xp)2+qy = (x-p)^2 + q

Has a turning point at (p,q)

So ... if you expand this (having put your minimum point in for p and q) you can equate to find a and b


Thank you, do you know if this is in the C1 book, because im looking through it and cant seem to find anything on it. Thanks again.
Reply 7
Which C1 book?

Edexcel it is chapter 2
(edited 12 years ago)
Reply 8
Original post by TenOfThem
Which C1 book?

Edexcel it is chapter 2


Edexcel yes, but i know how to complete the square, just not how to relate it to graphs, which isn't in chapter two.

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