[G8D]

(Original post by hassi94)
13" or 11" i7

That is as much as I shall narrow down Personally I'd probably get the 13" for the nicer resolution (I just can't work with something with that low resolution - even on an 11 inch screen - I like large resolutions ).

11" has better density though. So it'd be clearly even though smaller in size.

[Intriguing Alias]

(Original post by G8D)
11" has better density though. So it'd be clearly even though smaller in size.

It's more the amount of things I want to see on screen, rather than pixel density.

[Kenny_uk]

(Original post by mangoh)
http://www.bbc.co.uk/news/technology-18440979

tax for using ie7?

that **** cray


This was posted from The Student Room's iPhone/iPad App

If the website has to put a notable amount of effort into making it work with a browser more than 3/4 years old, why shouldn't that cost be passed onto the customers that cant be bothered/don't upgrade?

[Mad Vlad]

In other news, this brings back memories:

[Mad Vlad]

Great news! My desktop is running even smoother now that I've given it moar RAM memories.

In less good news... I now have a Blackberry for work... I'm still reading emails at 12:55AM In related news, Blackberry OS is ****. I've never had one before and they've given me quite a swish Bold, but it's just so clunky and unintuitive.

[Chrosson]

(Original post by hassi94)
http://www.amazon.de/N56VZ-S4066V-No...9596607&sr=8-1

Looking very 'Macbook Pro' but decently priced for what it is!

So confused for a few seconds. "Hundred thousand euros!?"

[ak137]

(Original post by Gofre)
-

I summon the mighty Spanish Waffle for some headphone advice
=P

Basically, I want some new headphones, bluetooth ones (wireless obviously lol). Budget = £30 or under. I can stretch to 35 quid but 40 is a bit too far. Also, the headband thingy, must be a proper headband, not one of those flimsy type, which I had before (God, I hated them -.-).
I was thinking this.

Any other suggestions or are those fine?

[Chrosson]

Y'know, I think the Sound and Vision subforum is getting lonely.

[Mad Vlad]

This.

[mikeyd85]

(Original post by Mad Vlad)
Great news! My desktop is running even smoother now that I've given it moar RAM memories.

In less good news... I now have a Blackberry for work... I'm still reading emails at 12:55AM In related news, Blackberry OS is ****. I've never had one before and they've given me quite a swish Bold, but it's just so clunky and unintuitive.

Welcome to hell. I hate BBOS. It's terrible in every way.

[Wednesday Bass]

My first venture into smartphones was a Blackberry. On a two-year contract. Needless to say I got rid of it before the end of the contract...

[S-man10]

LOL: http://www.bbc.co.uk/news/technology-18440979

[Ape Gone Insane]

For the first time in his life, mangoh got ahead of you there.

[S-man10]

Was this posted before?

[+ polarity -]

Hi, I have another nooby question

Is array[x][y] (where x and y refer to the row and column, natch) the correct way to refer to a particular 'cell' of a 2D array (this is for the Arduino, so it should be pretty much C++). There's this one function in my code which uses 2D arrays and it keeps overflowing, even at the first calculation!

Edit: I think I've got it! I was treating the numbers like row and cell numbers, but I think I should use consecutive numbers, all my 2D arrays are only 2x2.

arr

A B
C D

Is this correct: A = arr[0], B = arr[1], C = arr[2], D = arr[3]?

[+ polarity -]

In fact, I'll just turn my 2D arrays into 1D ones

[Mad Vlad]

(Original post by S-man10)
Was this posted before?

'fraid so.

It got ****canned.

[iCiaran]

(Original post by + polarity -)
Hi, I have another nooby question

Is array[x][y] (where x and y refer to the row and column, natch) the correct way to refer to a particular 'cell' of a 2D array (this is for the Arduino, so it should be pretty much C++). There's this one function in my code which uses 2D arrays and it keeps overflowing, even at the first calculation!

Edit: I think I've got it! I was treating the numbers like row and cell numbers, but I think I should use consecutive numbers, all my 2D arrays are only 2x2.

arr

A B
C D

Is this correct: A = arr[0], B = arr[1], C = arr[2], D = arr[3]?

It really depends how you visualise it, however I've heard that the "proper" way to see 2D arrays is as an array of arrays, so a 2D array [2][2] long would look a bit like this...

[+ polarity -]

(Original post by iCiaran)
It really depends how you visualise it, however I've heard that the "proper" way to see 2D arrays is as an array of arrays, so a 2D array [2][2] long would look a bit like this...

Makes sense

But I still couldn't get it to work. I think the problem is even earlier in my function than where the 2D arrays are! So I've had to abandon that section, again... and for the last time.

[Kenny_uk]

(Original post by Mad Vlad)
'fraid so.

It got ****canned.

Why was it deleted? we were hardly arguing like the previous "situation"