The Student Room Group
lol i had a silly idea this cant be right

treating it as a parralelogram

I took the larger piece but you could minus it from the original
Reply 2
No. Just did a triple integral on mathematica. It's very very very not pretty!
Reply 3
Infinity_Kev
lol i had a silly idea this cant be right

treating it as a parralelogram

I took the larger piece but you could minus it from the original
i'm interested in the other kind of cut, which goes down through the base, not the side.
Reply 4
SsEe
No. Just did a triple integral on mathematica. It's very very very not pretty!
oh. how depressing.
Reply 5
can you creat a picture chewwy??
Reply 6
If you meant the cylinder was cut by a plane passing through A and E like in the image below, then here's the answer for it.
You said we knew r, h, angle of cutting, say x (x = EAC)

Then EC = a = h.tanx
V(cylinder ACEF) = ¼πa².h
Then you only need to divide that volume by 2, you'll get the volume of the small piece

edit: forgot 1/4 lol
Reply 7
BCHL85
If you meant the cylinder was cut by a plane passing through A and E like in the image below, then here's the answer for it.
You said we knew r, h, angle of cutting, say x (x = EAC)

Then EC = a = h.tanx
V(cylinder ACEF) = ¼πa².h
Then you only need to divide that volume by 2, you'll get the volume of the small piece

edit: forgot 1/4 lol
ACEF is not a cylinder.
Reply 8
chewwy
ACEF is not a cylinder.

why not then???
edit: this is the picture in 1 face ... plz imagine your head... I am not good at drawing
Reply 9
BCHL85
why not then???
edit: this is the picture in 1 face ... plz imagine your head... I am not good at drawing
get a glass of water, fill it less than 50%, and tilt. you'll see.
Reply 10
chewwy
get a glass of water, fill it less than 50%, and tilt. you'll see.

actually u cant see that ACEF isnt a cylinder using the glass of water... although it's a nice idea :biggrin:
attachment shows why it's not a cylinder... (it's a top view)
Reply 11
yazan_l
actually u cant see that ACEF isnt a cylinder using the glass of water... although it's a nice idea :biggrin:
attachment shows why it's not a cylinder... (it's a top view)

oh .. I made a mistake ... lol
very stupid of me. Let me try again, then
Reply 12
I've got an idea that it is the
(final cross-sectional area / initial cross sectional area) h
but thats probably quite stupid.
Reply 13
I don't think you could do it with an integral (volume of revolution), could you? I mean any curve on a graph that I can think of would not revolve 360 degrees around the axis and give the desired shape. Hmmm....
Reply 14
the volume would depend on the angle of the cut, the height and the radius. I'm not sure about integrals on mathematica, but this is definately a very complicated problem. It's calculus of 4 variables ie. f(x,y,z,w). pfft, ask a cambridge mathmo lol.
Reply 15
partial derivatives?
Reply 16
Has anybody else tried doing it on mathematica?

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