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Logistic Function

I'm doing my Maths SL IA Type II - Population trends in China.

A logistic function will never reach it's upper bound, it will be an asymptote, continuing to infinity.
But does it start at zero? Or does the bottom half of the sigmoid curve continue to infinity too?

Thanks
Original post by robawalsh
I'm doing my Maths SL IA Type II - Population trends in China.

A logistic function will never reach it's upper bound, it will be an asymptote, continuing to infinity.
But does it start at zero? Or does the bottom half of the sigmoid curve continue to infinity too?

Thanks


As x approaches infinity logx or lnx approaches infinity.

As x approaches 0 lnx approaches negative infinity. This makes sense if you consider that logs are just exponents. That is you cannot raise a positive base to any power to make it a negative number.

e^y = x

lnx = y

x can never be negative as e is postive.
It's a physiological model, so it starts at the initial population size.
Physiological models generally aren't used into the values of negative time, as it doesn't make biological sense (if you would need to, it's best to incorporate a time delay instead) :smile:
Reply 3
Original post by Classical Liberal
As x approaches infinity logx or lnx approaches infinity.

As x approaches 0 lnx approaches negative infinity. This makes sense if you consider that logs are just exponents. That is you cannot raise a positive base to any power to make it a negative number.

e^y = x

lnx = y

x can never be negative as e is postive.


So X will never be negative, but can it reach zero?
Original post by robawalsh
So X will never be negative, but can it reach zero?


Can 0 = e^y ?

remember if y = 0 then e^y = 1 and if y = -1 then e^y = 1/e

Is there any y that makes e^y zero?
Reply 5
Original post by Classical Liberal
Can 0 = e^y ?

remember if y = 0 then e^y = 1 and if y = -1 then e^y = 1/e

Is there any y that makes e^y zero?


...1? :s-smilie:
Original post by robawalsh
...1? :s-smilie:


e^1 = e

You can't think of one because it does not exist. When x = 0 lnx is undefined.

You cannot raise a postive number to the power of anything and get it to equal 0 or be negative.

As x gets smaller and smaller and smaller lnx approaches negative infinity.

Watch some vids on the khan academy on limits, will make more sense then.
(edited 12 years ago)
Reply 7
Original post by Classical Liberal
e^1 = e

You can't think of one because it does not exist. When x = 0 lnx is undefined.

You cannot raise a postive number to the power of anything and get it to equal 0 or be negative.

As x gets smaller and smaller and smaller lnx approaches negative infinity.

Watch some vids on the khan academy on limits, will make more sense then.


Oh, I see. Kind of.
Thanks
Original post by robawalsh
Oh, I see. Kind of.
Thanks


http://www.khanacademy.org/video/introduction-to-limits--hd?playlist=Calculus

Go through the limits play list. Calculus makes a lot more sense when you understand limits.

Definitely worth getting a really robust understanding this concept, rather than a general rough idea.

(btw the technical name for the stuff we were discussing is domain and range so it worth knowing that aswell)
(edited 12 years ago)

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