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C3 Modulus

How would you work out |3x+2| = 1 ?

Would you use the same method as with inequalities?
Try using the "squaring method" for simple questions like these. Here's how to do it:

Square both sides: 3x+12=12|3x+1|^2 = 1^2
(3x+1)(3x+1)=1(3x+1)(3x+1) = 1
9x2+6x=09x^2+6x = 0
x(9x+6)=0x(9x+6) = 0

Solutions: x=0x = 0 or x=23x = \frac{-2}{3}
Original post by subzero0137
Try using the "squaring method" for simple questions like these. Here's how to do it:

Square both sides: 3x+12=12|3x+1|^2 = 1^2
(3x+1)(3x+1)=1(3x+1)(3x+1) = 1
9x2+6x=09x^2+6x = 0
x(9x+6)=0x(9x+6) = 0

Solutions: x=0x = 0 or x=23x = \frac{-2}{3}


You probably want to note that the question in the OP is 3x+2=1|3x+2| = 1, not 3x+1=1|3x+1| = 1.

Also please don't give out full solutions straight away. (I admit it is possible you changed the 2 to a 1 on purpose, in which case I'd suggest that as an example this is too similar)
(edited 12 years ago)
Reply 3
You could also find xx for when (3x+2)=1(3x+2) = 1 and when (3x+2)=1-(3x+2) = 1
Reply 4
Original post by eckothegecko
How would you work out |3x+2| = 1 ?

Would you use the same method as with inequalities?


Well you know that 3x+2=1 or -(3x+2)=1
work out the answer to x in each case.
x=(1-2)/3 or x=3/3
x=-1/3 or 1
Reply 5
the moduls just means what ever the equation is; negative or positive it has to become positive.

therefore 3x+2 |3x+2|

could be (3x+2)or(3x+2) (3x+2) or -(3x+2)

so you can have two answers, try using both of these answers and solve the equation

3x+2=1 |3x+2| = 1

you should get two different answers for x
put these two x values into your origional equation of y=... and you will get the two y values
Original post by EEngWillow
You probably want to note that the question in the OP is 3x+2=1|3x+2| = 1, not 3x+1=1|3x+1| = 1.

Also please don't give out full solutions straight away. (I admit it is possible you changed the 2 to a 1 on purpose, in which case I'd suggest that as an example this is too similar)


Oh...my bad.

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