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Graphs of functions

Bit confused about finding equations in terms of x :s-smilie:

f(x) = x2(1−x)x^2(1 - x)
Find the equation f(x + 1) in terms of x.

I don't get how the answer is −x(x+1)2-x(x + 1)^2?
Reply 1
Avatar for alexs2602
alexs2602
22
substitute x + 1 where x is, simple.
Just substitute in (x+1) wherever there is an x. Should come to (x+1)^2 (1-(x+1))
Which gives the answer :smile:
Reply 3
Avatar for rogersnm
rogersnm
4
f(x)=x2(1−x)f(x) = x^2(1-x)

f(x+1)=(x+1)2(1−(x+1))=(x+1)2(−x)=−x(x+1)2f(x+1) = (x+1)^2(1-(x+1)) = (x+1)^2(-x) = -x(x+1)^2
Original post by alexs2602
substitute x + 1 where x is, simple.

Even when x is in the bracket? or just when it's out?
Nevermind my question. Thanks everyone :smile:

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