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# AQA physics PHYA2 - 20/01/2012

Physics exam discussion - share revision tips in preparation for GCSE, A Level and other physics exams and discuss how they went afterwards.

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1. Re: AQA physics PHYA2 - 20/01/2012
(Original post by Machoo)
I hope it's on projectile motion as that is very easy to explain.
Yeah it is, however an experiment for it I do not know!

I only know that a stroboscope and a long exposure camera can be used to test acecleration, as the stroboscope (of known flash intervals) will highlight where the ball is per second whilst the camera takes pictures, and the distance between each picture of the ball will be larger the further down the ball falls.

what is an experiment for projectile motion!
2. Re: AQA physics PHYA2 - 20/01/2012
What is the 6 marker for projectile motion?? I haven't done that experiement
3. Re: AQA physics PHYA2 - 20/01/2012
This is a projectile motion question, the mark scheme wasn't very good in explaining it, so I've put a few of my ideas, I need your ideas too.

A dart is thrown horizontally at a speed of 8.0 ms^-1 towards the centre of a dartboard that is
2.0m away. At the same instant that the dart is released, the support holding the dartboard
fails and the dartboard falls freely, vertically downwards. The dart hits the dartboard in the
centre before they both reach the ground.

State and explain the motion of the dart and the dartboard, while the dart is in flight.

• Dart moves at a contant speed horizontally as there is no horizontal force
• But accelerates vertically downwards
• This results in a parabolic path
• The motion in the horizontal and vertical directions are independent of each other
• Dartboard accelerates vertically downwards at same rate as dart
• Gravity acting on dartboard is at the same rate as dart
• At a particular instant the vertical component of velocity is the same for dart and dartboard
4. Re: AQA physics PHYA2 - 20/01/2012
I think you can do the same experiment for projectile motion. Just explain that you'll do it by dropping a ball vertically and then by rolling a ball off of a slope and then letting it fall. This should give you two paths of the ball in your image. One of the ball just falling and one of the projectile motion. If then you want to go further, you can calculate the vertical and horizontal components of the projected ball. Hope the helps!

I'm resitting this module too but im most nervous about having to derive dsinΘ = nλ
5. Re: AQA physics PHYA2 - 20/01/2012
Tbh i think the content is fine for me..- the only problem for me is doing the exam in 1 hour 15...
6. Re: AQA physics PHYA2 - 20/01/2012
(Original post by MilanN)
I think you can do the same experiment for projectile motion. Just explain that you'll do it by dropping a ball vertically and then by rolling a ball off of a slope and then letting it fall. This should give you two paths of the ball in your image. One of the ball just falling and one of the projectile motion. If then you want to go further, you can calculate the vertical and horizontal components of the projected ball. Hope the helps!

I'm resitting this module too but im most nervous about having to derive dsinΘ = nλ
you won't have to derive any formulas I'm pretty sure, P206 in Nelson Thornes AS physics has a good diagram explaining where nlambda and d comes from.

sin theta equals the angle of diffraction of the beam

if sin theta = opposite/hypotenuse

sin theta = path difference (in n lambda)/ diffraction grating slit.
7. Re: AQA physics PHYA2 - 20/01/2012
(Original post by callmenighthawk)
you won't have to derive any formulas I'm pretty sure, P206 in Nelson Thornes AS physics has a good diagram explaining where nlambda and d comes from.
sin theta equals the angle of diffraction of the beam
if sin theta = opposite/hypotenuse
sin theta = path difference (in n lambda)/ diffraction grating slit.
on the official specification the only derivation i can find that we need to know is the one for

dSinθ = nλ

and i don't get it
..... can anyone explain it???
Last edited by wam-bam; 19-01-2012 at 19:18.
8. Re: AQA physics PHYA2 - 20/01/2012
(Original post by wam-bam)
on the official specification the only derivation i can find that we need to know is the one for

dSinθ = nλ

and i don't get it
..... can anyone explain it???
its a bit late now isn't it.
9. Re: AQA physics PHYA2 - 20/01/2012
Got 64/70 on the june 2011 paper still don't know how I got a B. I will get revenge tomorrow.

Anyone also doing D1 tomorrow?
10. Re: AQA physics PHYA2 - 20/01/2012
(Original post by albus)
its a bit late now isn't it.
i beg to differ, i was explained something this morning about something i didn't fully understand for my chemistry exam and it came up on the exam only 2 hours later .........

if anyone can help then please do. Thank you
11. Re: AQA physics PHYA2 - 20/01/2012
(Original post by Tyron3)
Got 64/70 on the june 2011 paper still don't know how I got a B. I will get revenge tomorrow.

Anyone also doing D1 tomorrow?
Someone posted that 60/70 was 120 UMS for one paper, A was 48! Such low boundarys!

I got a C in this, I must have done calculations incredibly wrong.
12. Re: AQA physics PHYA2 - 20/01/2012
(Original post by callmenighthawk)
Someone posted that 60/70 was 120 UMS for one paper, A was 48! Such low boundarys!

I got a C in this, I must have done calculations incredibly wrong.
no i'm doing M1 (and PHYA2) tomorrow (the way edexcel word their mechanics questions are horrible :/
have you done M1 by any chance, if so, how do you think it compared to D1 (easier or harder) ???
13. Re: AQA physics PHYA2 - 20/01/2012
(Original post by wam-bam)
i beg to differ, i was explained something this morning about something i didn't fully understand for my chemistry exam and it came up on the exam only 2 hours later .........

if anyone can help then please do. Thank you
http://i.imgur.com/PumYB.png

sorry for my crude drawing but this is how it's explaing

sin theta = angle of diffraction of the beam

sin theta = opposite/hypotenuse
sin theta = wavelength/distance between slits

re arranging that goes to

sin theta x distance between slits = wavelength (path difference)

I'm not sure if we have to kniow any more than that
Last edited by callmenighthawk; 19-01-2012 at 20:12.
14. Re: AQA physics PHYA2 - 20/01/2012
(Original post by wam-bam)
no i'm doing M1 (and PHYA2) tomorrow (the way edexcel word their mechanics questions are horrible :/
have you done M1 by any chance, if so, how do you think it compared to D1 (easier or harder) ???
I did M1 last year in the summer It's much more interesting although the questions vary, I almost fall asleep doing D1 papers but it is a easy 100 if your accurate and don't make mistakes.

(Original post by callmenighthawk)
Someone posted that 60/70 was 120 UMS for one paper, A was 48! Such low boundarys!

I got a C in this, I must have done calculations incredibly wrong.
I what you mean I think I messed up completely this time will be different I've learnt from my mistakes and I'm gonna make sure I read the questions carefully. Hopefully a lot of marks on mechanics and a 6 mark question on stationary waves.
Last edited by Tyron3; 19-01-2012 at 20:18.
15. Re: AQA physics PHYA2 - 20/01/2012
(Original post by callmenighthawk)
http://i.imgur.com/PumYB.png
sorry for my crude drawing but this is how it's explaing
sin theta = angle of diffraction of the beam
sin theta = opposite/hypotenuse
sin theta = wavelength/distance between slits
re arranging that goes to
sin theta x distance between slits = wavelength (path difference)
I'm not sure if we have to kniow any more than that
That has literally just clicked in my head, i didn't realise it was that simple!
Thank you!
16. Re: AQA physics PHYA2 - 20/01/2012
(Original post by Tyron3)
I did M1 last year in the summer It's much more interesting although the questions vary, I almost fall asleep doing D1 papers but it is a easy 100 if your accurate and don't make mistakes.

I what you mean I think I messed up completely this time will be different I've learnt from my mistakes and I'm gonna make sure I read the questions carefully. Hopefully a lot of marks on mechanics and a 6 mark question on stationary waves.
Stationary waves are a bit iffy, what I know from recall :

Nodes at either end of the wave
progressive waves in stationary waves have same amplitude & frequency
Progressive waves act in opposite directions, bounce of nodes, pass through each other and superimpose, forming supertrough/supercrest
Stationary waves do not transfer energy because antinodes/nodes are in fixed positions, nodes are at the end of the wave.
speed of wave = F x Length
17. Re: AQA physics PHYA2 - 20/01/2012
(Original post by wam-bam)
That has literally just clicked in my head, i didn't realise it was that simple!
Thank you!
It's only when going through the book with a greater understanding did I realise my mechanics teacher is bad at explaining.
18. Re: AQA physics PHYA2 - 20/01/2012
Good luck guys

May God help us all
19. Re: AQA physics PHYA2 - 20/01/2012
(Original post by ElMoro)
Good luck guys

May God help us all
Good luck!

Hopefully the number of questions on waves will be minimal.
20. Re: AQA physics PHYA2 - 20/01/2012
At times like these, we can only sit down and pray for the inevitable.

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