Can someone solve this please, I have made several attemps but can't get to the answer:
Find the second derivative of F(x)=ln(1+x^2). I can get the first derivative but cant get the second one. Show steps please!! The answer should be 2(1-x^2)/(1 + x^2)^2
Recall that the derivative of a logarithm, in the form ln(f(x)), is f(x)f′(x). Using this rule you get f′(x)=1+x22x. Now to get f′′(x) use the Quotient rule.
thanyou for the response. I can get the first derivative, the PROBLEM is the second derivative. I try and try and cant get it. If you can show it out with steps, would be great ^^
thanyou for the response. I can get the first derivative, the PROBLEM is the second derivative. I try and try and cant get it. If you can show it out with steps, would be great ^^
To get a derivative of a function in the form h(x)f(x) you basically do:
[h(x)]2h(x)f′(x)−f(x)h′(x)
So for your second derivative, use f(x)=2x,h(x)=x2+1
But i dont get the answer which i posted on my first thread
That's right so far,
but now all you have to do is simplify. So expand the numerator to get 2+2x^2 - 4x^2 so the numerator becomes 2-2x^2, then take out the common factor... then I hope you can go on from there