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AQA Core 3 Exam - 20/01/2012

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np, i'm the same. There really isn't any method behind doing it though, at A level anyway. It's just like you know sec^2 x goes to tanx

Found in past papers they do tend to put alot of question like by using qutient rule prove than than differentiates to tanx and what not, so might be a good idea to like run through proofs, I find they are always tricky because they always consist of funny ideas you have to work with

Reply 61

uxa595

Original post by Retro.spex

I understand that now, I guess I just wanted to know the theory behind it but I suppose I can worry about that when this exam is over :rolleyes:

Just noticed this but it may help you.

look at b)
It shows you cot x differentiates to -cosec^2 x
So all you had to do was use the knowledge from part b and flip the signs :smile:

I knew they wouldn't ask you something like that by itself...

Anywoo, I hope c3 is nothing like the c4 last june or i will screw.

(edited 12 years ago)

Reply 62

uxa595

Original post by chuckaduckitskat

Yh, a lot of the questions i've seen require you to use trig identities to solve the quotient rule questions.
Just make sure you now the main 3.
1+ tan^2 = sec^2
1+ cot^2 = cosex^2
sin^2 + cos^2 = 1

Reply 63

Mike1

Original post by H_Rattan

you know when they ask you to describe a series of transformations..does it matter which order u put them transformations in?

Best way to think of it is:
X -Translation
X -Stretch
X -Reflection
Y -Reflection
Y -Stretch
Y -Translation

Reply 64

Retro.spex

Original post by uxa595

Just noticed this but it may help you.

look at b)
It shows you cot x differentiates to -cosec^2 x
So all you had to do was use the knowledge from part b and flip the signs :smile:

I knew they wouldn't ask you something like that by itself...

Anywoo, I hope c3 is nothing like the c4 last june or i will screw.

Oh yeah! I didn't notice that either :redface:

Thanks again for helping :smile:

Just done the June 11 paper... I cannot believe the grade boundaries were virtually the same for that paper as the others.

Reply 65

f1mad

I hope it's a challenging one (leading to lower grade boundaries). :biggrin:

Reply 66

f1mad

Original post by Retro.spex

Oh yeah! I didn't notice that either :redface:

Thanks again for helping :smile:

Just done the June 11 paper... I cannot believe the grade boundaries were virtually the same for that paper as the others.

Looked easier than previous ones.

Reply 67

Retro.spex

Original post by f1mad

Looked easier than previous ones.

Are you serious? The previous ones are waaaaaay easier! I just got a B on the June 11 paper and I think if you stick to the methods it's not that hard, but they've thrown in a lot of nasty numbers to confuse people!

Reply 68

uxa595

i said C4 meaning core 4 not core 3.
the boundaries for that was stupidly low :smile:

c4 was 65/75 for 100ums, 58/75 for an A*, 51/75 for an A

core 3 in june 2011 was pretty easy i think.

Reply 69

OllyHV

Hi, are we expected to know how to draw the graphs of cosec, cot and sec?

Reply 70

hihihihihi

Original post by OllyHV

Hi, are we expected to know how to draw the graphs of cosec, cot and sec?

maybe but its just the top of the inverse if you know what i mean

Reply 71

Cath-ay

good luck everyone! hope it's a nice paper :smile:

Reply 72

OnimushaGTA

Original post by Cath-ay

good luck everyone! hope it's a nice paper :smile:

Thanks and to you too :smile:

However knowIng AqA, this paper is going to be a toughie! I can feel it!

Reply 73

Cath-ay

Original post by OnimushaGTA

Thanks and to you too :smile:

However knowIng AqA, this paper is going to be a toughie! I can feel it!

lol possibly - lower grade boundaries in that case. my maths teacher said that someone is going to get a nice paper today... knowing my luck, it probably won't be me :P

Reply 74

randyunknown

Original post by OnimushaGTA

Thanks and to you too :smile:

However knowIng AqA, this paper is going to be a toughie! I can feel it!

Nah, with several difficult ones leading up to this year, Im pretty sure well have a nicer one this time. Or atleast basic/routine questions leading up to a couple difficult ones at the end.

Reply 75

uxa595

Original post by randyunknown

Nah, with several difficult ones leading up to this year, Im pretty sure well have a nicer one this time. Or atleast basic/routine questions leading up to a couple difficult ones at the end.

The june 2011 paper was a joke, so we may be due a hard one

Reply 76

Retro.spex

Original post by uxa595

The june 2011 paper was a joke, so we may be due a hard one

I can't believe people think the June paper is easier than other ones :confused:

But anyway, would you be able to explain this question to me?

y = ln(6x)

(a)State the x-coordinate of the point of intersection of the curve with the x-axis

So I know it would be

0=ln(6x)

But where does x =1/6 come from? This is a log law isn't it?

Reply 77

vedderfan94

Original post by Retro.spex

I can't believe people think the June paper is easier than other ones :confused:

If x=1/6, y=ln1=0 which is where it crosses the x axis.

Reply 78

Retro.spex

Original post by vedderfan94

If x=1/6, y=ln1=0 which is where it crosses the x axis.

Oh I see, so you're basically just supposed to use the fact that you know ln1 = 0 and figure out what 6 is multiplied by to get that?

Thank you :biggrin:

Reply 79

Retro.spex

Original post by vedderfan94

If x=1/6, y=ln1=0 which is where it crosses the x axis.

Just one other question,

the second part asks you to find dy/dx, so I assumed that it's just the normal rule where lnx becomes 1/x, but because you use the chain rule it would be 6/x. The mark scheme says 1/x though, but how can that be?