OCR MEI C1: ***POST-EXAM DISCUSSION*** - 13th January 2012

I'm gna write what I put for some of my answers...all the ones I can remember. Maybe we can start an unofficial mark scheme as quite a few ppl seem to be requesting one.
1) y = -1/5x + 6 1/5
2) (i) 1/3
(ii) 32 x^10 y^-3
Dunno what q number but 5(x+1.5)^2+0.75 ...y value 0.75
The circle had centre (2,0) and crossed y-axes at +-4
10) area = 10 square units. To prove that d was an equal distance from all point I wrote that AC is hypotenuse so its midpoint is equally as far from all points...idk if it's right. Don't remember the coordinates of D
11) N shaped graph crossing y-axis at 12...unsure of x-axis coordinates. (iii) x = 0 x = 4.5 x = -3 (it might've been 3 and -4.5...don't remember what I put)
12) k = 14 and -6 (again, could've been 6 and -14)

(edited 12 years ago)

Reply 27

oh and for the translations...I think I translated the first one up by three units and the second one left by two

Reply 28

ImComplicated

Original post by jjshonde

Can someone just put the answers up, it will save all the posts about individual questions

Can you remember any of the questions I am putting together a mark scheme

Reply 29

For the => qs, I put <=> for the first and <= for the second

Reply 30

Original post by Xotol

Last part of 12 was -14 and 6.

I thought so too. By using b^2 -4ac

Reply 31

Original post by Polioz

uhhh... I ended up with 0=4k^2-32k-256 ..... so k^2-8-64

Resit for me as well... I think i got everything right bar ... a 3 mark section A Question where i didnt simplify properly ... and 12 iii i think... ? what was ur final equation . do you think il get method marks

If you had of carried on with that you were right. The answer was -14 and 6

Reply 32

i did b^2 - 4ac = 0

but ended up with a equation which was like k^2-8k+84

then did quadratic formula...

Reply 33

Original post by viktorija3105

Can anyone remember how they got 10 for the area of a triangle? Coz I had like the base was 8 and height was 5 so i ended up with area =20

Yeah, it was 2root10*root10/2 which became 10

Reply 34

dont even remember a question asking for the area of the triangle lol.

Reply 35

Original post by TimetoSucceed

dont even remember a question asking for the area of the triangle lol.

Hahaha it was part of the question asking you to prove that AB and BC were perpendicular :wink:

Reply 36

Original post by TimetoSucceed

i did b^2 - 4ac = 0

but ended up with a equation which was like k^2-8k+84

then did quadratic formula...

Yeah that was right. If you had of carried on, you would have got -14 and 6

Reply 37

Original post by henryc

Yeah that was right. If you had of carried on, you would have got -14 and 6

will i get any marks?

Reply 38

Original post by nadster

Hahaha it was part of the question asking you to prove that AB and BC were perpendicular :wink:

oh snapp was that the right angle?

what i did was do pythagoras and as pythagoras only works on right angle edges i managed to prove it that way, seriously i remember it now lol

Reply 39