The Student Room Group

M1 Edexcel Pre-Exam Discussion thread (Tips/Papers/MS) - Please don't merge

I will create two types of thread.

A pre-exam thread, where I will upload papers, MS, boundaries, revision tips. I will update this thread and use it for each exam season.

A post-exam thread, where I will upload my model answers the day following the exam and I will try to answer questions about the paper.

Scroll to see replies

Reply 7
PAST BOUNDARIES



Session 100' 90' 80' 70' 60' 50' 40'
Jan-01 75 71 67 59 51 43 36
Jun-01 68 61 54 47 40 33 26
Jan-02 75 69 63 56 49 42 35
Jun-02 67 59 51 43 36 29 22
Nov-02 74 67 60 53 46 39 32
Jan-03 75 69 62 54 46 39 32
Jun-03 75 69 63 55 47 39 32
Nov-03 75 67 59 51 44 37 30
Jan-04 73 66 59 52 45 38 32
Jun-04 75 69 62 52 42 32 23
Nov-04 72 65 58 51 44 37 31
Jan-05 75 69 62 54 47 40 33
Jun-05 75 69 63 54 46 38 30
Jan-06 70 62 54 46 39 32 25
Jun-06 75 71 67 58 49 41 33
Jan-07 75 69 62 54 46 38 30
Jun-07 75 71 66 57 48 39 30
Jan-08 74 66 58 50 42 35 28
Jun-08 73 65 57 49 41 33 25
Jan-09 63 56 49 42 35 28 21
Jun-09 73 64 55 46 38 30 22
Jan-10 75 68 61 53 45 38 31
Jun-10 75 68 61 53 45 37 29
Jan-11 75 70 64 57 50 43 37
Jun-11 75 68 60 52 44 37 30

Reply 8
Revision notes
Reply 9
ADVICE

LEAVE EVERY ANSWER TO 2SF or 3SF

you will lose a mark if you write down a more exact answer in a question involving gravity because you will be using a rounded value of g (9.8 to 2sf). The exam board will accept 3sf as it is standard and g = 9.806 so 3sf answers are normally still correct.


LEARN YOUR ASSUMPTIONS

Rod - Plank will act in a straight line
Uniform - Weight acts at the centre
Particle - Weight acts at a single point (normally end of a rod)
Light - no extra weight added to system, same tension
Smooth pulley - same tension either side
Inextensible - same acceleration in both systems

Things you often ignore in a model

air resistant
constant coefficient of friction
constant acceleration


FORCE ACTING ON PULLEY (INCLINED PLANE)

Just learn this formula, it always works.... plane inclined at angle A to the horizontal

RF = 2T x Cos ( (90-A)/2 )


LEARN ABOUT WEIGHT

Weight = mass x gravity

if mass is given x by g. If weight is given DON'T x by g.

Weight perp to plane = mg cos A
Weight parallel to plane = mg sin A

if A = 30

Weight perp to plane = 0.866mg
Weight parallel to plane = 0.5mg


IMPULSE

Don't bother learning mv-mu or whatever it is. In M1 you are ONLY ever asked for the magnitude of impulse.

Impulse = Change in Momentum, the difference between initial and final momentum.

Impulse measured in Ns.


VECTORS

learn to use matrix/vector notation, makes it a lot easier than i and j

Use your common sense, if necessary draw out the problem on a coordinate grid.

Vel = change in pos / time

acc = change in vel / time

postion at any time = initial pos + t x vel

vel at any time = initial vel + t x acc

Velocity gives you direction

moving parallel to i means that j component of velocity equation is zero

moving parallel to j means that i component of velocity equation is zero

moving NE means that i and j components of velocity equation are equal

moving NW means that - i (component of velocity equation) = j (component of velocity equation)

moving parallel to 2i + 3j means that 1.5i (component of velocity equation)= j (component of velocity equation)


THRUST

Go over the Thrust question from June 09, it is going to come up again at some point

Tension is a pulling force, tensions will point towards each other in a connecting object

Thrust is a pushing force, thrusts will point away from one another in a rigid connecting object


STATICS / DYNAMICS

Understand the difference between the two

Look for moving at constant speed, this means acc = 0, hence the resultant force is zero (equilibrium).

RF = mass x acc


MOMENTS

Don't forget the basic equation that RF vertically = 0

so all the sum of all the forces up must equal the sum of all the forces down



RESOLVING FORCES

When splitting up a force into its components, if you ClOSe the angle it is F x cos A
(edited 12 years ago)
Reply 10
So gonna be ready by 1pm on Friday! Thanks Arsey
Reply 11
'moving parallel to 2i + 3j means that 1.5i (component of velocity equation)= j (component of velocity equation)'

isn't it 1.5j and 1i ???
Reply 12
no,

if you multiply your i component by 1.5 this will be equivalent to your j component

for example

v = (2t + 1)i + (5t - 6)j find the time it is parallel to 2i + 3j

(2t + 1) x 1.5 = 5t - 6

3t + 1.5 = 5t - 6

7.5 = 2t

t = 3.75 3hrs 45 min
Do we take g = 9.8 or 9.81?

And how many decimals off are they okay with? Like if I get 74.8 instead of 74.7, will I still get the accuracy mark?
Reply 14
FORCE ACTING ON PULLEY (INCLINED PLANE)

Just learn this formula, it always works.... plane inclined at angle A to the horizontal

RF = 2T x Cos ( (90-A)/2 )


does anoybody know what he/she means by '2T' im quite confused, any help would be appriciated because this sort of a question is usually 5 marks, and a shortcut like this would help:tongue:
Reply 15
Original post by Parthenon93

Original post by Parthenon93
Do we take g = 9.8 or 9.81?

And how many decimals off are they okay with? Like if I get 74.8 instead of 74.7, will I still get the accuracy mark?


they don't specify, but usually 9.8, 9.81 is generally used in physics
Original post by Arsey
,,,



Hey Arsey, sorry for posting this here but are you planning to upload solutions for S1 at midnight? :smile:
Original post by moosecanon
does anoybody know what he/she means by '2T' im quite confused, any help would be appriciated because this sort of a question is usually 5 marks, and a shortcut like this would help:tongue:


T is the tension in the string/rope :smile: x
Reply 18
Original post by Arsey
...


Quick question about impulse, when doing I=M(V-U) do you take the direction of the particle in to account?
E.g. A of 2kg was going left with speed 3ms-1 after collision its direction of motion was reversed and was travelling with speed 4ms-1
Would the impulse be (taking right as positive)
I=2(4- -2)
I=12ns?
Original post by POWW!
Quick question about impulse, when doing I=M(V-U) do you take the direction of the particle in to account?
E.g. A of 2kg was going left with speed 3ms-1 after collision its direction of motion was reversed and was travelling with speed 4ms-1
Would the impulse be (taking right as positive)
I=2(4- -2)
I=12ns?


Yes you do take the direction of the speed into account mate :smile: x

Latest

Trending

Trending