[hetty123]

(Original post by plan_up_sleeve)
You put in a lot of time and effort on something that a lot of people will come back and look at and it will help them so of course you deserve a special mention :P

yeahhh!!!!
thanks niaghez

[Saffrony]

you guys know the question on the 2 part synthesis thing?
was it reduce the aldehyde, then condensation to join COOH and OH?? (which i did)

OR was it the other way round

[adilh301]

(Original post by Saffrony)
you guys know the question on the 2 part synthesis thing?
was it reduce the aldehyde, then condensation to join COOH and OH?? (which i did)

OR was it the other way round

Yeah you got it the right way round it was compound c-> oxalondrone

[otrivine]

(Original post by adilh301)
Yeah you got it the right way round it was compound c-> oxalondrone

in the exam i wrote all the reagents and they were correct so will they mark the correct ones as well as the functional groups?

[adilh301]

(Original post by otrivine)
in the exam i wrote all the reagents and they were correct so will they mark the correct ones as well as the functional groups?

Should do

[Conal09]

(Original post by ellieHA)
No I don't think it does because then it would be +1 and zwitterions have an overall charge of 0

I wondered about that in the exam but remembered that as they have the overall 0 charge it'd make no sense for them both to get changed

Good point, damn. 2 marks, *poof*.

[charlotte.yellow]

(Original post by Nerdatious)
I thought it was an aldehyde too! It can't have been a ketone there wasn't another methyl group attached?

I thought aldehyde too?

[charlotte.yellow]

(Original post by windo)
so am i right in saying "Because it can donate a lone pair of electrons to form a covalent bond" or did i have to say the N donates a lone pair of electrons.

Yes you were right

[otrivine]

the question on isoelectric i said there is no overall charge as positive and negative cancel ? is that ok for 1 mark

[heeeello]

for the one where we had to draw an Amino acid at the isoelectric point, were we meant to put nh3+ instead of nh2 on the nh2 on the r group?

[racheatworld]

(Original post by heeeello)
for the one where we had to draw an Amino acid at the isoelectric point, were we meant to put nh3+ instead of nh2 on the nh2 on the r group?

Nope. The R group stayed as NH2 because if the R group was protonated to become NH3+, then there would be 2 positive charges and 1 negative charge, so the overall charge would not be 0 and therefore the amino acid would not actually be a zwitterion.

[racheatworld]

(Original post by plan_up_sleeve)
And I think that wraps it up pretty well, thank you niaghez! Best of luck to everyone who took this exam, you really have done well, if not on the paper, then at least you've become wiser!

Summer 2012, make it one that you'll always remember!

Thank you to all useful contributors in this thread!

P.s. If I were the exam, I would tell everyone to go away as I have been argued over around 2600 times, over 134 pages of TSR and a period of almost 24 hours.

Aw so sweet!

I want everyone to come back in August and tell us what they got on this paper because I guarantee that everyone will have done better than expected and grade boundaries will be low (hopefully)!

[clad in armour]

[QUOTE=Wotevatreva;38216334]

(Original post by Megantheminx)


You've done well today, ain't ya?!!!

I think theres been an error, I did not write that

[windo]

(Original post by SmithytheDrummer)
Even though you may think this, but just look at this thread which, although not entirely representative of the whole country, will give a decent representation of what a large amount of people thought of this exam. The majority of people who thought that the exam was hard. In January, most people thought this was easy, it's one of the things that scared me most by being on that thread. The grade boundaries are bound to be lower.

How many raw marks do you think will be required to get an E on this paper. since that is waht im required to get my target grade.

[windo]

hey guys i know this is an exam thread but, if i get 39/40 raw marks in the coursework how much UMS would that be out of 60?

[Cath-ay]

(Original post by windo)
hey guys i know this is an exam thread but, if i get 39/40 raw marks in the coursework how much UMS would that be out of 60?

About 58 ums. 37/40 has been an A* (54 ums) in the past.

[windo]

(Original post by Cath-ay)
About 58 ums. 37/40 has been an A* (54 ums) in the past.

Ok thank you. Can u guesstimate what raw marks would be required to get an E on this paper this thread is about.

[windo]

can any one guess how many raw marks would be needed to get an E on this exam?

[windo]

How many marks do you guys think i will get for the 9 marks question for writing this...

M/Z value furthest to the right = 164 so MR = 164.

$ = x ppm - singlet so no Hs on adjacent C atom.
$ = x ppm - triplet so 2 Hs on adjacent C atom
$ = X ppm - triplet so 2 Hs on adjacent C atom
$ = x ppm - multiplet of 6 so 5 Hs on adjacent C atom.

Then i drew the Correct structure


how many marks out of 9 will i get for this.

[hetty123]

(Original post by windo)
How many marks do you guys think i will get for the 9 marks question for writing this...

M/Z value furthest to the right = 164 so MR = 164.

$ = x ppm - singlet so no Hs on adjacent C atom.
$ = x ppm - triplet so 2 Hs on adjacent C atom
$ = X ppm - triplet so 2 Hs on adjacent C atom
$ = x ppm - multiplet of 6 so 5 Hs on adjacent C atom.

Then i drew the Correct structure


how many marks out of 9 will i get for this.

probably the full nine marks, as you've mentioned delta values(1-2m), splitting patterns(1-2m), what they show(2-4m), you understand that m/z is Mr (~1m)and you got the correct structure(2-4m)

well done!!

why do you keep asking for the grade boundaries for an E???
you've done pretty well, since you got this one right

i think an E will be about 24-26

so as long as you got another 17 on definitions and working out for something i think you have at least a definite E grade or higher

ps. what is your target grade?????