[jetskiwavedunkno]

(Original post by Mr Inquisitive)
When - just apply that to the and substitute the values of x for the gradients you require.

is it x=3 graient =27
x=5 gradient =75

x=-3 gradient =27??

[Gemini92]

(Original post by jetskiwavedunkno)
is it x=3 graient =27
x=5 gradient =75

x=-3 gradient =27??

Those are all right.

[jetskiwavedunkno]

(Original post by raheem94)
Only the gradient at x=3 is correct, others are wrong, try again.

How did you differentiated x^3? maybe you are making a mistake there.

you are wrong

[jetskiwavedunkno]

(Original post by Gemini92)
Those are all right.

awww thank you! xx

[Mr Inquisitive]

(Original post by jetskiwavedunkno)
is it x=3 graient =27
x=5 gradient =75

x=-3 gradient =27??

Yes, they're correct.

[jordan-s]

(Original post by raheem94)
Only the gradient at x=3 is correct, others are wrong, try again.

I'm afraid the gradient at 3 is also incorrect?

3x^2 when x = 3 gives 3 multiplied by 3^2, which is 3 x 9 = 27..

Ooops, too late! You've got it now anyway.

[jetskiwavedunkno]

(Original post by Mr Inquisitive)
Yes, they're correct.

for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=

y= x^3-2 at x=1 gradient=

y= 4x^3 at x=1 gradient=

how do i do this

[Gemini92]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=

y= x^3-2 at x=1 gradient=

y= 4x^3 at x=1 gradient=

how do i do this

Exactly the same way as the others, differentiate the function and sub in the x value. (Remember that constants differentiate to 0)

[mr tim]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=

y= x^3-2 at x=1 gradient=

y= 4x^3 at x=1 gradient=

how do i do this

the same way as you did before differentiate each equation, except this time you only need to sub in one x value for each equation, which is 1

[jetskiwavedunkno]

(Original post by Gemini92)
Exactly the same way as the others, differentiate the function and sub in the x value. (Remember that constants differentiate to 0)

y=4x^2+2 at x=1 gradient=10??

[jetskiwavedunkno]

(Original post by mr tim)
the same way as you did before differentiate each equation, except this time you only need to sub in one x value for each equation, which is 1

for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=10??

[mr tim]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=10??

remember that the constant [ie: number without the x next it] differentiated gives 0.

[jetskiwavedunkno]

(Original post by mr tim)
remember that the constant [ie: number without the x next it] differentiated gives 0.

for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient= 8

y= x^3-2 at x=1 gradient= 3

y= 4x^3 at x=1 gradient=12

are they right

[Mr Inquisitive]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient=

y= x^3-2 at x=1 gradient=

y= 4x^3 at x=1 gradient=

how do i do this

Take of the value, set the value you obtain equal to zero, then substitute in .

Spoiler:

Show

First one would be , so follow on from there.

[jetskiwavedunkno]

(Original post by Mr Inquisitive)
Take of the value, set the value you obtain equal to , then substitute in .

Spoiler:

Show

First one would be , so follow on from there.

for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient= 8

y= x^3-2 at x=1 gradient= 3

y= 4x^3 at x=1 gradient=12

are they right

[mr tim]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient= 8

y= x^3-2 at x=1 gradient= 3

y= 4x^3 at x=1 gradient=12

are they right

yes they are all right.

[Mr Inquisitive]

(Original post by jetskiwavedunkno)
for each curve find the gradient at the given point.

y=4x^2+2 at x=1 gradient= 8

y= x^3-2 at x=1 gradient= 3

y= 4x^3 at x=1 gradient=12

are they right

Yes, they are.

[raheem94]

(Original post by jetskiwavedunkno)
you are wrong

(Original post by jordan-s)
I'm afraid the gradient at 3 is also incorrect?

3x^2 when x = 3 gives 3 multiplied by 3^2, which is 3 x 9 = 27..

Ooops, too late! You've got it now anyway.

Sorry, i also calculated it as 27 but i don't know why did i wrote the gradient at x=3 is correct. Actually i was busy at another thread as well so i just got confused.

Btw, thanks for indicating my mistake.

[jetskiwavedunkno]

(Original post by raheem94)
Sorry, i also calculated it as 27 but i don't know why did i wrote the gradient at x=3 is correct. Actually i was busy at another thread as well so i just got confused.

Btw, thanks for indicating my mistake.

dw about it raheem

[jetskiwavedunkno]

(Original post by Mr Inquisitive)
Yes, they are.

Thank you sir