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need help on dy/dx

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Original post by Mr Inquisitive
Yes, they are.


Find the equations of the normals to the curves at the given point

y=(x+1)^2 at x=0

y=4/x at x=1

answers in form ax+by+c=0

how do i do this
also can some1 check if this is right

find the equations of the tangents to the curves at the given points

y=5x^2+1 at x=2 y=50?

y=3x^2-4x at x=3 y=14??
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Original post by jetskiwavedunkno
Find the equations of the normals to the curves at the given point

y=(x+1)^2 at x=0

y=4/x at x=1

answers in form ax+by+c=0

how do i do this


Find the first derivative, sub x=0x=0 to find the value of the gradient.

mm multiplied by z=11/m=zz = -1 \Rightarrow -1/m = z.

Put the value of zz into the equation yy1=z(xx1)y-y1=z(x-x1), where z=z = gradient of the normal.
(edited 12 years ago)

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