Integrating to Find Area Under a Curve
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Re: Integrating to Find Area Under a CurveWikipedia does a pretty good job of giving a rough idea why it's the case, check out the 'Geometric intuition' bit of http://en.wikipedia.org/wiki/Fundame...em_of_calculus
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Re: Integrating to Find Area Under a CurveThe answer to this question is a lot easier to understand graphically, but basically you have to imagine that in
, the f(x) is the height of a rectangle and the dx is some arbitrarily small width of that rectangle. The integral means, in essence, adding up all the rectangles - which amounts to finding the total area under the curve.
Edit: this is not really super helpful in terms of answering your question, but is roughly relevant and amused me. Why don't I think of things like this?
Last edited by teamnoether; 29-02-2012 at 19:21. -
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Re: Integrating to Find Area Under a CurveOr, if you want to go more in depth, check out the Riemann Integral(Original post by Claree)
Please could someone explain to me WHY calculating a definite integral finds you the area under a curve?
tbh, it depends what you define an integral to be. -
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Re: Integrating to Find Area Under a CurveI am not sure if i am right, but in my opinion this is the case,(Original post by Claree)
Please could someone explain to me WHY calculating a definite integral finds you the area under a curve?
You would have probably studied calculating area by using trapezium rule, in that rule we use strips.
In integration, we use infinite strips.
The area of one strip will be, Area=
where delta x is very small, almost zero.
Now summing the strips,
As
, the summation becomes integration,
Hope i am correct.
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Re: Integrating to Find Area Under a CurveStrictly speaking, it's because the integral is what we define the "area under a curve" to be, and the fact it's consistent with the definition of area for simple shapes is what allows this definition to make sense.
Last edited by matt2k8; 29-02-2012 at 23:27. -
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Re: Integrating to Find Area Under a Curvethe area (called the Riemann integral) is the limit of the riemann sum over the certain interval - end points (a,b), divided into intervals of equal length b-a/l, with a point c in each interval. Sum is then SIGMA i=0 to n-1 of f(c_i)(x_i+1-x_i)
basically:f(c_0)(x_1-x_0)+f(c_1)(x_2-x_1)+f(c_2)(x_3-x_2)+.....+f(c_n-1)(x_n-x_n-1)
