Easy differentiation?
Maths and statistics discussion, revision, exam and homework help.
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Re: Easy differentiation?You're using, or should be, the product rule on the bracket term in your original expression. The derivative of everything in the brackets is simply -1.(Original post by RAFecon)
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Re: Easy differentiation?Yes I can see where it comes from now if I expand the summation, thanks. But I would like to know automatically when using the product rule.(Original post by steve10)
Expand the summation term by term for the 1st three terms, say. Then work out the derivatives. You'll see where the -q1 come from then.
I think I'm missing something. How do the brackets differentiate to -1 when you differentiate w.r.t. q1(Original post by ghostwalker)
You're using, or should be, the product rule on the bracket term in your original expression. The derivative of everything in the brackets is simply -1. -
Re: Easy differentiation?Differentiating what's inside the brackets term by term. There's only one term in q1, and that's the -q1 under the summation sign (giving -1).(Original post by RAFecon)
I think I'm missing something. How do the brackets differentiate to -1 when you differentiate w.r.t. q1
It's the same as steve10 is suggesting, but doing it in your head. -
Re: Easy differentiation?oh, ok. thanks(Original post by ghostwalker)
Differentiating what's inside the brackets term by term. There's only one term in q1, and that's the -q1 under the summation sign (giving -1).
It's the same as steve10 is suggesting, but doing it in your head.