[The Hedonist]

I'm quite stuck on this

1
______________ dx

(1-x^2)^1.5)

Substitution is x=sinθ and the limits given are 0.5 and 0

any help/advice would be appreciated!

[Deep456]

(Original post by The Hedonist)
I'm quite stuck on this

1
______________ dx

(1-x^2)^1.5)

Substitution is x=sinθ and the limits given are 0.5 and 0

any help/advice would be appreciated!

1/(cos^2theta)^1.5 go from there . Also remember to change the limits.

[Jodin]

Well what have you tried? Certainly that substitution looks like a good idea.

[just george]

(Original post by Deep456)
1/(cos^2theta)^1.5 go from there . Also remember to change the limits.

but surely:

so

so the integral would be

[Deep456]

(Original post by just george)
but surely:

dx/dtheta = cos(theta) so dx = cos(theta) dtheta

so the integral would be cos(theta) / (cos^2theta)^1.5 dtheta

All I have done is subbed in sin theta and used the identity. I haven't done anything else.

What you have done is also correct ,yes.

[just george]

(Original post by Deep456)
All I have done is subbed in sin theta and used the identity. I haven't done anything else.

sorry yeah it just looked a bit misleading to me, looked like you were saying the integral was

The Hedonist - basically just use the substitution given, remember to change between dx and dtheta, the limits, and then hopefully you will be left with something you can integrate