Results are out! Find what you need...fast. Get quick advice or join the chat
x

Unlock these great extras with your FREE membership

  • One-on-one advice about results day and Clearing
  • Free access to our personal statement wizard
  • Customise TSR to suit how you want to use it

Integration help!

Announcements Posted on
Find your uni forum to get talking to other applicants, existing students and your future course-mates 27-07-2015
Win top prizes in our mega results day giveaway... 24-07-2015
  1. Offline

    ReputationRep:
    I'm quite stuck on this

    1
    ______________ dx

    (1-x^2)^1.5)

    Substitution is x=sinθ and the limits given are 0.5 and 0

    any help/advice would be appreciated!
  2. Offline

    ReputationRep:
    (Original post by The Hedonist)
    I'm quite stuck on this

    1
    ______________ dx

    (1-x^2)^1.5)

    Substitution is x=sinθ and the limits given are 0.5 and 0

    any help/advice would be appreciated!
    1/(cos^2theta)^1.5 go from there . Also remember to change the limits.
  3. Offline

    ReputationRep:
    Well what have you tried? Certainly that substitution looks like a good idea.
  4. Offline

    ReputationRep:
    (Original post by Deep456)
    1/(cos^2theta)^1.5 go from there . Also remember to change the limits.
    but surely:

    \frac{dx}{d\theta} = cos\theta so  dx = cos\theta d\theta

    so the integral would be  \frac {cos\theta}{(cos^2\theta)^1^.^5} d\theta
  5. Offline

    ReputationRep:
    (Original post by just george)
    but surely:

    dx/dtheta = cos(theta) so dx = cos(theta) dtheta

    so the integral would be cos(theta) / (cos^2theta)^1.5 dtheta
    All I have done is subbed in sin theta and used the identity. I haven't done anything else.

    What you have done is also correct ,yes.
  6. Offline

    ReputationRep:
    (Original post by Deep456)
    All I have done is subbed in sin theta and used the identity. I haven't done anything else.
    sorry yeah it just looked a bit misleading to me, looked like you were saying the integral was  \frac{1}{(cos^2\theta)^1^.^5}

    The Hedonist - basically just use the substitution given, remember to change between dx and dtheta, the limits, and then hopefully you will be left with something you can integrate

Reply

Submit reply

Register

Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?
  2. this can't be left blank
    this email is already registered. Forgotten your password?
  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By joining you agree to our Ts and Cs, privacy policy and site rules

  2. Slide to join now Processing…

Updated: March 6, 2012
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Poll
Did you lie on your personal statement?
New on TSR

Results are coming...

No sweat. Here's all you need to make sure you're ready

Study resources
x

Think you'll be in clearing or adjustment?

Hear direct from unis that want to talk to you

Get email alerts for university course places that match your subjects and grades. Just let us know what you're studying.

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.