OCR B F335 - Chemistry by Design - 13th June 2012
Chemistry exam discussion - share revision tips in preparation for GCSE, A Level and other chemistry exams and discuss how they went afterwards.
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Re: OCR B F335 - Chemistry by Design - 13th June 2012Thank you very much(Original post by Hazel247)
If you count the longest chain of carbons first then you know what the end part will be, and you can then add on the functional groups in alphabetical order. And remember you always number the functional groups as low as you possibly can (so think about which end you start counting from!)
Hope this helps
would you be able to give me an example please
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Re: OCR B F335 - Chemistry by Design - 13th June 2012thats because they are very unstable and they cannot be obtained(Original post by Princess Kawaii)
Explain why synthons are not often used to make the required compound?
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Re: OCR B F335 - Chemistry by Design - 13th June 2012erm you should know the equation off by hear which is quiet easy to remember and just remember the conditions(Original post by Jasmine_777)
how much detail do we need to know about the Haber process and the N2 cycle ??
..you should be alright with haber process if you know that i think
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Re: OCR B F335 - Chemistry by Design - 13th June 2012Because the majority of the time the synthons don't exist, they're not real compounds.(Original post by Princess Kawaii)
Explain why synthons are not often used to make the required compound? -
Re: OCR B F335 - Chemistry by Design - 13th June 2012they're also just hypothetical(Original post by Princess Kawaii)
Explain why synthons are not often used to make the required compound? -
Re: OCR B F335 - Chemistry by Design - 13th June 2012all I know is N2 + 3H2 <===> 2NH3(Original post by master_blaster66)
erm you should know the equation off by hear which is quiet easy to remember and just remember the conditions
..you should be alright with haber process if you know that i think
All gaseous.
What are the conditions?
Also, how much do you know about the N2 cycle?
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Re: OCR B F335 - Chemistry by Design - 13th June 2012no(Original post by Jasmine_777)
do we need to know solubility product, Ksp ? -
Re: OCR B F335 - Chemistry by Design - 13th June 2012That's still an A isn't it??(Original post by Ilyas)
messed up jan 2012 paper... only got 84/120 raw. Damn enzymes! -
Re: OCR B F335 - Chemistry by Design - 13th June 2012Yep, but I want a high A* in this so I can slack off in chemistry of materials (next one), I'm better at chem by design, been getting consistent A*'s in all other papers...(Original post by Anthony Soprano)
That's still an A isn't it??Last edited by Venomilys; 11-06-2012 at 22:31. -
Re: OCR B F335 - Chemistry by Design - 13th June 2012Ahh i see now(Original post by Ilyas)
Yep, but I want a high A* in this so I can slack off in chemistry of materials (next one), I'm better at chem by design, been getting consistent A*'s in all other papers...
Best of luck this time round, and if worst come to worst, you still have an A
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Re: OCR B F335 - Chemistry by Design - 13th June 2012what did you get in f334 in jan?(Original post by Ilyas)
Yep, but I want a high A* in this so I can slack off in chemistry of materials (next one), I'm better at chem by design, been getting consistent A*'s in all other papers... -
Re: OCR B F335 - Chemistry by Design - 13th June 2012F would be -2..you ignore the no. of moles(Original post by Princess Kawaii)
when you work out the oxidation number of soemthing do u take into account the big numbers infron of the compound? Or do u ignore them?
e.g. 2CuF2 is F = -2 or -4?
thnx
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Re: OCR B F335 - Chemistry by Design - 13th June 2012Wouldn't F just be -1?(Original post by master_blaster66)
F would be -2..you ignore the no. of moles