C1 indices
Maths and statistics discussion, revision, exam and homework help.
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Re: C1 indicesI want to make it clear to you that i didn't gave you neg rep, i don't know who gave it.(Original post by tnetennba)
You could use logarithms:
Log 4^x = Log 0.25
x Log 4 = Log 0.25
x= (Log 0.25)/(Log 4)
x=-1
I think that you thought that i gave you a neg rep so you neg repped me, right? -
Re: C1 indicesThe bases are fine as it is, I don't see why you are changing it to 2. It's quite easy to see it using the base 4.(Original post by Waqar.)
Make them both to the base of 2 and then equate the indices...
4 ^ x = 2^2x
1/4 = 2^-2
2^2x = 2^-2
equate both indices...
2x = -2
x = -1
In conclusion: Equate both bases and then equate the indices and simplify.Last edited by roar558; 16-03-2012 at 09:46. -
Re: C1 indicesFair enough, if I'm honest I'm not 100% clear on what's covered in each module having done a different specification.(Original post by raheem94)
ln is in C3, while OP is studying C1 so she probably doesn't knows logarithms. -
Re: C1 indicesYou can show it using the ln rule however you apparently haven't been taught it yet so the other method would be comparing powers (make sure the base on both sides are equal).(Original post by jessica_anne_clu)
but how would you go about it? I know the answer is -1 but I don't know how you'd get it