C1 indices

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  1. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C1 indices
    (Original post by tnetennba)
    You could use logarithms:
    Log 4^x = Log 0.25
    x Log 4 = Log 0.25
    x= (Log 0.25)/(Log 4)
    x=-1
    I want to make it clear to you that i didn't gave you neg rep, i don't know who gave it.

    I think that you thought that i gave you a neg rep so you neg repped me, right?
  2. Waqar.'s Avatar
    • Exalted Member
    • Posts: 342
    Re: C1 indices
    Make them both to the base of 2 and then equate the indices...

    4 ^ x = 2^2x
    1/4 = 2^-2

    2^2x = 2^-2

    equate both indices...
    2x = -2
    x = -1

    In conclusion: Equate both bases and then equate the indices and simplify.
  3. roar558's Avatar
    • Overlord in Training
    • Posts: 2,609
    Re: C1 indices
    (Original post by Waqar.)
    Make them both to the base of 2 and then equate the indices...

    4 ^ x = 2^2x
    1/4 = 2^-2

    2^2x = 2^-2

    equate both indices...
    2x = -2
    x = -1

    In conclusion: Equate both bases and then equate the indices and simplify.
    The bases are fine as it is, I don't see why you are changing it to 2. It's quite easy to see it using the base 4.
    Last edited by roar558; 16-03-2012 at 09:46.
  4. roar558's Avatar
    • Overlord in Training
    • Posts: 2,609
    Re: C1 indices
    (Original post by raheem94)
    ln is in C3, while OP is studying C1 so she probably doesn't knows logarithms.
    Fair enough, if I'm honest I'm not 100% clear on what's covered in each module having done a different specification.
  5. roar558's Avatar
    • Overlord in Training
    • Posts: 2,609
    Re: C1 indices
    (Original post by jessica_anne_clu)
    but how would you go about it? I know the answer is -1 but I don't know how you'd get it
    You can show it using the ln rule however you apparently haven't been taught it yet so the other method would be comparing powers (make sure the base on both sides are equal).
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