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variation of parameters

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    the function is defined piecewise by
    h(x) = 0 when 0<x<1 and h(x) =x-1 when x>1!!
    Solve the initial value problem (Ay)(x)=h(x) , Ay=y''-y y(0)=y'(0)=0
    by finding green's function for A using variation of parameters!!!
    First of all m^2-1=0 -> m=1,m=-1 !!
    then y1=c1f1+c2f2 here i stuck!! i dont know how to continue!!! how i found the functions here?? anyomne help?


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