Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Drift Velocity (electricity)!?

Just a question which I cant seem to get:

Calculate the drift velocity of electrons along a wire of diameter 0.32mm, carrying a current of 2.4A

n= 8.5 x 10 to the power of 28 m-3

e= 1.6 x 10 to the power of -19 C

I = nAqv

therefore v=I/(nAq)

A=pi(r squared) = pi(diameter/2)squared = pi x (0.32 x 10 to the -3/2) squared
=8.04 x 10 to the -8

so v=2.4/(nAq) - just substitue
=2.195 x 10 to the -3 ms-1 = 2.2 mms-1

OP

How did you get "=2.195 x 10 to the -3 ms-1 = 2.2 mms-1"

Thanks
From John

oh the extra m in 'mms-1' is the milli..so its 2.2 millimetre per sec
but this is pretty fast though for an electron :smile:

:smile:

if its for the first part then
______________________ 2.4 ________________________
(8.5 x 10 to the 28th)(8.04 x 10 to the -8)(1.6 x 10 to the -19)

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