Redox Equilibria
Chemistry discussion, revision, exam and homework help.
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Re: Redox Equilibria
I dont know, sorry 
I would have said two, as you've got 6e- on the LHS, and 3e- on the right, so I would have doubled the number of moles on the RHS, giving 2 moles...
sorry, that is of no use what so ever...
best to ask teacher tomorrow at college perhaps?
unless someone else can shed some light on this. im curious now, i wonder what we're doing wrong??
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Re: Redox EquilibriaThank you. I asked my teacher, he said the mark scheme got it wrong.(Original post by HeatherJarvo)
I dont know, sorry
I would have said two, as you've got 6e- on the LHS, and 3e- on the right, so I would have doubled the number of moles on the RHS, giving 2 moles...
sorry, that is of no use what so ever...
best to ask teacher tomorrow at college perhaps?
unless someone else can shed some light on this. im curious now, i wonder what we're doing wrong??
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Re: Redox Equilibriathat's a scary thought isn't it? It's possible to lose marks on the exam by getting the answer correct.... eek!!(Original post by Gattsu)
Thank you. I asked my teacher, he said the mark scheme got it wrong. -
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Re: Redox Equilibria(Original post by Gattsu)
Given the following redox reactions:
How many moles of iron (II) ethandioate FeC2O4 are oxidised by 1 mol of dichromate Cr2O72–(aq)?
(I thought the answer was 2. However the mark scheme says 3, and does not explain why.)
Couldnt figure out how you form iron (II) ethandioate FeC2O4 in the first place !?(Original post by HeatherJarvo)
I dont know, sorry
I would have said two, as you've got 6e- on the LHS, and 3e- on the right, so I would have doubled the number of moles on the RHS, giving 2 moles...
sorry, that is of no use what so ever...
best to ask teacher tomorrow at college perhaps?
unless someone else can shed some light on this. im curious now, i wonder what we're doing wrong??
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Re: Redox EquilibriaWhy can you not form it?(Original post by arvin_infinity)
Couldnt figure out how you form iron (II) ethandioate FeC2O4 in the first place !?
Last edited by thegodofgod; 29-03-2012 at 23:05. -
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Re: Redox EquilibriaFe2+ + (COOH)2 --> [Fe(COO)2] + 2H+(Original post by arvin_infinity)
Oh no..I meant , how you form it according the the equation given to you -
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Re: Redox EquilibriaCOOH is not given to us !!!(Original post by charco)
Fe2+ + (COOH)2 --> [Fe(COO)2] + 2H+
I guess I misunderstood the question
