Mechanics clarification needed (EPE)

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  1. Like_A_G6's Avatar
    • Benevolent Member
    • Posts: 858
    Mechanics clarification needed (EPE)
    Hi,

    During A Levels in M3 were taught that the change in EPE was equal to final E.P.E. - initial E.P.E, which is equal to λy²/2L - λx²/2L as mentioned on chapter 2 of this page:

    http://www.thestudentroom.co.uk/showthread.php?t=771543

    Therefore the work done in stretching an elastic spring with modulus λ from its natural length L to a length (L+x) is λx²/2L
    However, at uni we are now taught that in stretching a spring or string, the tensile force is equal to kx (which we were told at A Level physics) and the work done in stretching an elastic spring is kx²/2 (integral of force is work done) which translates to λx²/2 if k and λ are the same thing (both modulus of elasticity). Now, λx²/2L and λx²/2 are not the same thing so was wondering if i'm missing something obvious here...

    Can anyone help me understand?
  2. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Mechanics clarification needed (EPE)
    (Original post by Like_A_G6)
    Hi,

    During A Levels in M3 were taught that the change in EPE was equal to final E.P.E. - initial E.P.E, which is equal to λy²/2L - λx²/2L as mentioned on chapter 2 of this page:

    http://www.thestudentroom.co.uk/showthread.php?t=771543



    However, at uni we are now taught that in stretching a spring or string, the tensile force is equal to kx (which we were told at A Level physics) and the work done in stretching an elastic spring is kx²/2 (integral of force is work done) which translates to λx²/2 if k and λ are the same thing (both modulus of elasticity). Now, λx²/2L and λx²/2 are not the same thing so was wondering if i'm missing something obvious here...

    Can anyone help me understand?
    In physics we study,  T=kx

    In M3 we study,  T=\dfrac{\lambda x}{l}

    So  k=\dfrac{ \lambda }{l}

     k \not= \lambda
  3. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Mechanics clarification needed (EPE)
    (Original post by Like_A_G6)
    However, at uni we are now taught that in stretching a spring or string, the tensile force is equal to kx (which we were told at A Level physics) and the work done in stretching an elastic spring is kx²/2 (integral of force is work done) which translates to λx²/2 if k and λ are the same thing (both modulus of elasticity). Now, λx²/2L and λx²/2 are not the same thing so was wondering if i'm missing something obvious here...
     \dfrac{kx^2}{2} = k \times \dfrac{x^2}{2} = \dfrac{\lambda}{l} \times \dfrac{x^2}{2} = \dfrac{\lambda x^2}{2l}
  4. Like_A_G6's Avatar
    • Benevolent Member
    • Posts: 858
    Re: Mechanics clarification needed (EPE)
    (Original post by raheem94)
    In physics we study,  T=kx

    In M3 we study,  T=\dfrac{\lambda x}{l}

    So  k=\dfrac{ \lambda }{l}

     k \not= \lambda
    Ah ok. Thanks for helping me again raheem Much appreciated
  5. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Mechanics clarification needed (EPE)
    (Original post by Like_A_G6)
    Ah ok. Thanks for helping me again raheem Much appreciated
    No problem, you are welcome.
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