AQA CHEM1: 15th May 2012

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  1. TaraBelle's Avatar
    • Exalted and Worshipped Member
    Re: AQA CHEM1: 15th May 2012
    (Original post by Salmanftw)
    im sure trends are only associated with period 2 and 3.
    4 would mean knowledge of transition metals.
    They've done it before. From Gallium to Selenium. However it's just the same as it would be for the elements above them so no biggie
  2. SHAH :)'s Avatar
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    • Posts: 61
    Re: AQA CHEM1: 15th May 2012
    (Original post by Jack_Smith)
    1s2.2s2.sp6.3s2.3p6.4s2.3d10.4p6 .5s2.4d10.5p1
    but i dont get why you dont fill the 4f sub shell before the 5s one :s
  3. Holy Cherrys's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by TaraBelle)
    They've done it before. From Gallium to Selenium. However it's just the same as it would be for the elements above them so no biggie
    ahh okay, so just your typical increase due to increased nuclear charge?
    what dicks
  4. TaraBelle's Avatar
    • Exalted and Worshipped Member
    Re: AQA CHEM1: 15th May 2012
    (Original post by joker12345)
    What on earth are T shapes?!
    It's the same trigonal bipyramidal, but imagine two of the bonds being lone pairs instead
  5. Voglie's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by wenger16)
    how do you work out how many electrons in each shell?
    The number of e-'s an element has is equal to the atomic number of that element.

    The s sub-shell stores 2 electrons,

    the p sub-shell stores 6 electrons,

    and the d sub-shell stores 10 electrons.

    The sub-shell order is: 1s 2s 2p 3s 3p 4s 3d 4p, and depending on which type of sub-shell it is, that's how many e-'s you're allowed to put into it.

    Just keep on filling the sub-shells in that order until you have filled in all the e-'s the element has.
  6. dobe's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by wenger16)
    how do you work out how many electrons in each shell?
    the 1s orbital fills first, then the 2s, 2p, 3s, 3p, 4s, 3d, etc
    s orbitals have 2 electrons, p orbitals have 6 electrons, d orbitals have 10 and f orbitals have 14.
    you then just count along until you have used all the electrons.
    for example, phosphorus will be 1s2, 2s2, 2p6, 3s2, 3p3 (this equals to 15 electrons)
    sorry if this made no sense whatsoever
  7. Holy Cherrys's Avatar
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    Re: AQA CHEM1: 15th May 2012
    What do you guys reckon is the hardest part of the bonding chapter?
  8. wenger16's Avatar
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    Re: AQA CHEM1: 15th May 2012
    Can someone explain all the shapes business? like trignal bypyramid etc?
  9. Madara's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by Salmanftw)
    What do you guys reckon is the hardest part of the bonding chapter?
    The hardest part for me is working out some of the wierd bond angles like in NH3 its a triangular pyramid right but why is its bond angle 107? thats the only one which confuses me. You'd expect is to be 120-2.5 so 117.5 so could someone explain this?
  10. Madara's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by W4L1Y)
    Hi
    how do you turn dm^3 into m^3
    and cm^3 into m^3

    This is for Pv = nRT
    To convert dm3 to m3 you *1000

    to convert cm3 into m3 you *100^3 so (100*100*100)= so your *1,000,000
  11. bad8oy's Avatar
    • Peer Of The TSR Realm
    Re: AQA CHEM1: 15th May 2012
    (Original post by Madara)
    The hardest part for me is working out some of the wierd bond angles like in NH3 its a triangular pyramid right but why is its bond angle 107? thats the only one which confuses me. You'd expect is to be 120-2.5 so 117.5 so could someone explain this?
    its tetrahedral so 109.5-2.5=107
    it has 4 pairs of electrons therefore tetrahdral but has the shape of a triangular pyramid because of the 3 arms.
  12. Holy Cherrys's Avatar
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    Re: AQA CHEM1: 15th May 2012
  13. Madara's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by bad8oy)
    its tetrahedral so 109.5-2.5=107
    it has 4 pairs of electrons therefore tetrahdral but has the shape of a triangular pyramid because of the 3 arms.
    Ohh I see... thanks you helped clear some stuff up
  14. AspiringDoctor's Avatar
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    • Location: West Midlands, UK
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    Re: AQA CHEM1: 15th May 2012
    (Original post by Salmanftw)
    My teacher printed this for me.

    http://www.google.co.uk/imgres?q=VSE...5&tx=117&ty=55
    That's really useful - thank you!
  15. Holy Cherrys's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by AspiringDoctor)
    That's really useful - thank you!
    yeah, cram that table like hell.
    try to remember it as, 4 bonding pairs 3 lone pairs/3 bonding pairs 1 lone pair etc.
  16. W4L1Y's Avatar
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    Re: AQA CHEM1: 15th May 2012
    to convert dm^3 into m^ 3 isnt it X 10^-2
  17. Voglie's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by Madara)
    To convert dm3 to m3 you *1000

    to convert cm3 into m3 you *100^3 so (100*100*100)= so your *1,000,000
    Stop confusing people :P.

    I've replied to this question earlier in the thread.

    cm^3 -> m^3 = DIVIDE BY 10^6 (or multiply by 10^-6)
    dm^3 -> m^3 = DIVIDE BY 10^3 (or multiply by 10^-3)
  18. Holy Cherrys's Avatar
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    Re: AQA CHEM1: 15th May 2012
    forget the standard forms.

    cm3 to m3 is divide by 1000000.
    dm3 to m3 is divide by 1000
    cm3 to dm3 is divide by 1000

    vice versa = multiplacation
  19. popnit's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by TaraBelle)
    8a is literally just asking you how many neutrons, electrons and protons have a go?
    Hence why I said part 2
  20. ambrin ox's Avatar
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    Re: AQA CHEM1: 15th May 2012
    (Original post by joker12345)
    What on earth are T shapes?!
    Oh, if you see something with 2 lone pairs and 3 bond pairs its t shape, basically trigonal planar with 120 bond angle
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